Answer:
H₀: µ ≤ $8,500; H₁: µ > $8,500
z= +1.645
Step-by-step explanation:
From the given problem As average cost of tuition and room and board at a small private liberal is less than the financial administrator As hypothesis is true.
As standard deviation is $ 1,200
α = 0.05
H₀: µ ≤ $8,500
if the null hypothesis is true then value for critical z is +1.645.
The population at the end of the year is
(year-end population) = (beginning population) + 6.5%×(beginning population)
= (beginning population)×(1 + 0.065)
That same multiplier applies each year for 9 years. We know that we can use an exponent to describe repeated multiplication, so the population after 9 years will be ...
(ending population) = (beginning population)×(1.065)⁹
After 9 years, the population will be 350,000×1.065⁹ ≈ 616,900.
Answer:
Your answer.
8x + y = 95.........(1)
2x + 7y = 71........... (2)
Y = 95-8x........ (3)
Put this value in eq 2
Then x = 11
Put x value in eq 3
Y = 7
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Step-by-step explanation:
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