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irga5000 [103]
3 years ago
15

The U.S. Department of Housing and Urban Development​ (HUD) uses the median to report the average price of a home in the United

States. Why do you think HUD uses the​ median?
Mathematics
1 answer:
MatroZZZ [7]3 years ago
3 0

Answer:

Step-by-step explanation:

given that the U.S. Department of Housing and Urban Development​ (HUD) uses the median to report the average price of a home in the United States.

We know that mean, median and mode are measures of central tendency.

Mean is the average of all the prices while median is the middle entry when arranged in ascending order.

Mean has the disadvantage of showing undue figure if extreme entries are there. i.e. outlier affect mean.

Suppose a price goes extremely high, then mean will fluctuate more than median.

So median using gives a reliable estimate since median gives the middle price and equally spread to other sides.

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A researcher claims that the mean of the salaries of elementary school teachers is greater than the mean of the salaries of seco
Brut [27]

Answer:

t=\frac{(48250-45630)}{\sqrt{\frac{3900^2}{26}+\frac{5530^2}{24}}}}=1.921  

df=n_{A}+n_{B}-2=26+24-2=48

Since is a one sided test the p value would be:

p_v =P(t_{(48)}>1.921)=0.0303

If we compare the p value and the significance level given \alpha=0.05 we see that p_v so we can conclude that we have enough evidence to reject the null hypothesis, and we can conclude that the mean for elementary school teachers is significantly higher than the mean for secondary teachers at 5% of significance

Step-by-step explanation:

Data given and notation

\bar X_{A}=48250 represent the mean of elementary teachers

\bar X_{B}=45630 represent the mean for secondary teachers

s_{A}=3900 represent the sample standard deviation for elementary teacher

s_{B}=5530 represent the sample standard deviation for secondary teachers

n_{A}=26 sample size selected

n_{B}=24 sample size selected  

\alpha=0.05 represent the significance level for the hypothesis test.

t would represent the statistic (variable of interest)

p_v represent the p value for the test (variable of interest)

State the null and alternative hypotheses.

We need to conduct a hypothesis in order to check if the mean of the salaries of elementary school teachers is greater than the mean of the salaries of secondary school teachers, the system of hypothesis would be:

Null hypothesis:\mu_{A}-\mu_{B}\leq 0

Alternative hypothesis:\mu_{A}-\mu_{B}>0

We don't know the population deviations, so for this case is better apply a t test to compare means, and the statistic is given by:

t=\frac{(\bar X_{A}-\bar X_{B})}{\sqrt{\frac{s^2_{A}}{n_{A}}+\frac{s^2_{B}}{n_{B}}}} (1)

t-test: "Is used to compare group means. Is one of the most common tests and is used to determine whether the means of two groups are equal to each other".

Calculate the statistic

We can replace in formula (1) the info given like this:

t=\frac{(48250-45630)}{\sqrt{\frac{3900^2}{26}+\frac{5530^2}{24}}}}=1.921  

P-value

The first step is calculate the degrees of freedom, on this case:

df=n_{A}+n_{B}-2=26+24-2=48

Since is a one sided test the p value would be:

p_v =P(t_{(48)}>1.921)=0.0303

Conclusion

If we compare the p value and the significance level given \alpha=0.05 we see that p_v so we can conclude that we have enough evidence to reject the null hypothesis, and we can conclude that the mean for elementary school teachers is significantly higher than the mean for secondary teachers at 5% of significance

5 0
3 years ago
Consider the continuous random variable x, which has a uniform distribution over the interval from 110 to 150. The probability t
Virty [35]

Answer:

The probability that x will take on a value between 120 and 125 is 0.14145

Step-by-step explanation:

For uniform distribution between a & b

Mean, xbar = (a + b)/2

Standard deviation, σ = √((b-a)²/12)

For 110 and 150,

Mean, xbar = (150 + 110)/2 = 130

Standard deviation, σ = √((150-110)²/12 = 11.55

To find the probability that x will take on a value between 120 and 125

We need to standardize 120 & 125

z = (x - xbar)/σ = (120 - 130)/11.55 = - 0.87

z = (x - xbar)/σ = (125 - 130)/11.55 = - 0.43

P(120 < x < 125) = P(-0.87 < x < -0.43)

We'll use data from the normal probability table for these probabilities

P(120 < x < 125) = P(-0.87 < x < -0.43) = P(z ≤ -0.43) - P(z ≤ -0.86) = 0.33360 - 0.19215 = 0.14145

Hope this Helps!!!

3 0
3 years ago
Someone pleaseeeee answer (you may have to click the picture to see all of the problem)
Leto [7]
X + 47= 147

hope that helps 
3 0
3 years ago
What is the percent of change from 50 to 23?
Taya2010 [7]

Answer:

50 is the old value and 23 is the new value. In this case we have a negative change (decrease) of -54 percent because the new value is smaller than the old value. Using this tool you can find the percent decrease for any value.

7 0
3 years ago
Read 2 more answers
2 (4y + 3 + y) hellppp
Yanka [14]

Answer:

10y + 6 hope this helps :)

Step-by-step explanation:

3 0
3 years ago
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