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3 years ago

Please help!! i’ll mark best answer brainliest!!

Mathematics

1 answer:

Dafna1 [17]3 years ago

6 0

Answer:

Z = 13

Step-by-step explanation:

Both of the angles should equal 90.

2z + 5 + 5z - 6 = 7z - 1

7z - 1 = 90

7z - 1 + 1 = 90 + 1

7z = 91

7z ÷ 7 = 91 ÷ 7

Z = 13

Hope that helped you and have a wonderful day!

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PLEASE EXPLAIN WHAT THESE MEAN- WORTH 30 POINTS AND ILL GIVE BRAINLIEST

Keith_Richards [23]

Answer:

Where is The question at? O_O

4 0

2 years ago

Which represents the solution of the graphed system of equations, y=x^2-2x and y=-2x-1

elena55 [62]

Answer:

x = √(-1) = i

Since the value of √(-1) is not real.

The system has no real solution.

Step-by-step explanation:

The solution to the system of equations is at the point where they intercept each other.

y1 = y2

For the given equation;

y=x^2-2x and y=-2x-1

To get the where they intercept, we will equal both equations;

y=x^2-2x = -2x-1

x^2 - 2x = -2x - 1

x^2 - 2x + 2x + 1 =0

x^2 +1 = 0

x^2 = -1

x = √(-1) = i

Since the value of √(-1) is not real.

The system has no real solution.

6 0

3 years ago

Reagan scored 1140 on the SAT. The distribution of SAT scores in a reference population is normally distributed with mean 1000 a

krok68 [10]

Answer:

Jessie scored higher than Reagan.

Step-by-step explanation:

We are given that Reagan scored 1140 on the SAT. The distribution of SAT scores in a reference population is normally distributed with mean 1000 and standard deviation 100.

Jessie scored 30 on the ACT. The distribution of ACT scores in a reference population is normally distributed with mean 17 and standard deviation 5.

For finding who performed better on the standardized exams, we have to calculate the z-scores for both people.

1. <u>Finding z-score for Reagan;</u>

Let X = distribution of SAT scores

SO, X ~ Normal( $\mu=1000, \sigma^{2}=100^{2}$ )

The z-score probability distribution for the normal distribution is given by;

Z = $\frac{X-\mu}{\sigma}$ ~ N(0,1)

where, $\mu$ = population mean = 1000

$\sigma$ = standard deviation = 100

Now, Reagan scored 1140 on the SAT, that is;

z-score = $\frac{1140-1000}{100}$ = 1.4

2. <u>Finding z-score for Jessie;</u>

Let X = distribution of ACT scores

SO, X ~ Normal( $\mu=17, \sigma^{2}=5^{2}$ )

The z-score probability distribution for the normal distribution is given by;

Z = $\frac{X-\mu}{\sigma}$ ~ N(0,1)

where, $\mu$ = population mean = 17

$\sigma$ = standard deviation = 5

Now, Jessie scored 30 on the ACT, that is;

z-score = $\frac{30-17}{5}$ = 2.6

This means that Jessie scored higher than Reagan because Jessie's standardized score was 2.6, which is 2.6 standard deviations above the mean and Reagan's standardized score was 1.4, which is 1.4 standard deviations above the mean.

6 0

3 years ago

You are planning to save for retirement over the next 35 years. to do this, you will invest $870 a month in a stock account and

DaniilM [7]

Go to mathpapa thats what i use

6 0

3 years ago

What is the quotient in simplified form ? Need help please

Gre4nikov [31]

Answer:

$-\dfrac{4a^{12}b^8}{5}$

Step-by-step explanation:

The applicable rules of exponents are ...

$\dfrac{1}{a^{-b}}=a^b\\\\a^ba^c=a^{b+c}$

Your ratio simplifies to ...

$\dfrac{-8a^8b^{-2}}{10a^{-4}b^{-10}}=-\dfrac{4}{5}a^{8-(-4)}b^{-2-(-10)}\\\\=-\dfrac{4a^{12}b^8}{5}$

_____

Please note that simplifying the constants, -8/10 to -4/5, eliminates half the answer choices. Since exponents are only multiplied when a power is raised to a power, you can pretty much eliminate the second choice as being unreasonable. ((a^b)^c = a^(bc))

8 0

3 years ago