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Gala2k [10]
3 years ago
10

In Triangle BCD, BC=BD, and angle B =13x-35, angle C = 5x-19, angle D=2x+14. Find the measure of each angle

Mathematics
1 answer:
aleksandr82 [10.1K]3 years ago
5 0

Answer:

B = 108

C = 36

D = 36

Step-by-step explanation:

Given

B =13x - 35

C = 5x - 19

D=2x+14

BC = BD

Required

Determine the measure of each angle

The angles in a triangle sum up t 180. i.e.

B + C + D = 180

Since BC = BD, then C = D

B + C + D = 180 can then be rewritten as:

B + C + C = 180

B + 2C = 180

Substitute values for B and C

13x - 35 + 2(5x - 19) = 180

Open Bracket

13x - 35 + 10x - 38 = 180

Collect Like Terms

13x + 10x = 180 + 38 + 35

23x= 253

Divide both sides by 23

x = 11

To get the measure of each angle, substitute 11 for x in the expressions of B, C and D

B =13x - 35

B = 13 * 11 - 35

B = 108

C = 5x - 19

C = 5 * 11 - 19

C = 36

D=2x+14

D = 2 * 11 + 14

D = 36

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Answer:

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<h2>\red { \orange {\boxed {\boxed{Answer}}}}</h2><h2>= 0.8</h2><h2>=  \frac{8}{10}</h2><h2>=  \frac{8 \div 2}{10 \div 2}</h2><h2>=  \frac{4}{5}</h2>

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