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IRINA_888 [86]
3 years ago
8

I really need help with this question! Can somebody solve it and show the steps.....?

Mathematics
1 answer:
Natalka [10]3 years ago
3 0

Answer:

ok so orders of operation.

Step-by-step explanation:

parenthesis,brachets: 2{3[9+4(2)-4]}

2{3[13×2-4]}

then we take whats inside the brackets and use order of operations there

13×2-4

parenthesis:none

exponents:none

multiplication: 13×2=26

division:none

addition: none

subtraction:26-4=22

then you're left with the equation:

2{3[26]}

clearly we aren't done with the brackets

so we do:

3×26=78

we're left with:

2{78}=156

your answer=156

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Please solve with explanation (high points)
IgorLugansk [536]

So, we know that:

A=\dfrac{1}{2}ab\\P=a+b+c\\a^2+b^2=c^2

We also know that (a+b)^2=a^2+2ab+b^2. We will use that fact to find c in terms of A and P.

A=\dfrac{1}{2}ab\Rightarrow 2ab=4A\\P=a+b+c\Rightarrow a+b=P-c

Therefore:

(P-c)^2=c^2+4A\\P^2-2cP+c^2=c^2+4a\\2cP=P^2-4A\\c=\dfrac{P^2-4A}{2P}

7 0
2 years ago
To make fruit punch for a party, we need 4 1⁄2 gallons of ginger ale, 1 gallon of strawberry juice, 2 3⁄4 gallons of frozen oran
lina2011 [118]

For this case we convert the mixed numbers to fractions:

4 \frac {1} {2} = \frac {2 * 4 + 1} {2} = \frac {9} {2}\\2 \frac {3} {4} = \frac {4 * 2 + 3} {4} = \frac {11} {4}

Now we add the fractions:

\frac{9} {2}+1+ \frac {11} {4} + \frac {1} {8} =

We find the least common multiple of the denominators. The l.c.m is 8, then we divide by each denominator and multiply the result by each numerator.

\frac {36 + 8 + 22 + 1} {8} =\\\frac {67} {8} =

8,375

Thus, the punch recipe implies 8.375 gallons. If we convert to a mixed number we have:

8 \frac {3} {8} gallons

Answer:

8 \frac {3} {8}gallons

4 0
3 years ago
If the area of a triangular kite is 60 square feet and its base is 10 feet, find the height of the kite.
11Alexandr11 [23.1K]
The area of the triangular kite would be 12 feet
3 0
2 years ago
Rhombus with diagonal lengths 9 ft and 4 ft. ( what's the area ? )
Alexeev081 [22]

Answer:

18

Step-by-step explanation:

4 0
2 years ago
The combined math and verbal scores for students taking a national standardized examination for college admission, is normally d
kipiarov [429]

Answer:

The minimum score that such a student can obtain and still qualify for admission at the college = 660.1

Step-by-step explanation:

This is a normal distribution problem, for the combined math and verbal scores for students taking a national standardized examination for college admission, the

Mean = μ = 560

Standard deviation = σ = 260

A college requires a student to be in the top 35 % of students taking this test, what is the minimum score that such a student can obtain and still qualify for admission at the college?

Let the minimum score that such a student can obtain and still qualify for admission at the college be x' and its z-score be z'.

P(x > x') = P(z > z') = 35% = 0.35

P(z > z') = 1 - P(z ≤ z') = 0.35

P(z ≤ z') = 1 - 0.35 = 0.65

Using the normal distribution table,

z' = 0.385

we then convert this z-score back to a combined math and verbal scores.

The z-score for any value is the value minus the mean then divided by the standard deviation.

z' = (x' - μ)/σ

0.385 = (x' - 560)/260

x' = (0.385×260) + 560 = 660.1

Hope this Helps!!!

8 0
3 years ago
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