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andrew11 [14]
3 years ago
13

Lmno is a parallelogram if nm = X + 11 and OL = 2x+4 find the value of x and then find NM and OL

Mathematics
1 answer:
devlian [24]3 years ago
7 0
If you draw out lmno as a parallelogram, then lo is always going to be opposite of nm which means they are equal to each other.  nm = ol or x+11=2x+4 or 7 = x,  then nm = ol = 18...
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9. To order books from an online site, the buyer must open an account. The buyer needs a username and a password.
slega [8]

Answer:

a)

i)208827064576

ii)62990928000

b)

i)28179280429056

ii)15214711438080

c)

i)899194740203776

ii)607681858331520

Step-by-step explanation:

a)

i)The alphabet consists of 26 letters.

For the first letter of the username there are 26 options.

For the second letter of the username there are 26 options.

For the third letter of the username there are 26 options.

For the fourth letter of the username there are 26 options.

For the fifth letter of the username there are 26 options.

For the sixth letter of the username there are 26 options.

For the seventh letter of the username there are 26 options.

For the eighth letter of the username there are 26 options.

To get the number of the possible usernames we multiply the number of options for each letter: 26 x 26 x 26 x 26 x 26 x 26 x 26 x 26 =26^8=208827064576

ii) If letter cannot be repeated.

For the first letter of the username there are 26 options.

For the second letter of the username there are only 25 options.

For the third letter of the username there are only 24 options.

For the fourth letter of the username there are only 23 options.

For the fifth letter of the username there are only 22 options.

For the sixth letter of the username there are only 21 options.

For the seventh letter of the username there are only 20 options.

For the eighth letter of the username there are only 19 options.

To get the number of the possible usernames we multiply the number of options for each letter: 26 x 25 x 24 x 23 x 22 x 21 x 20 x 19 =62990928000

b) 26 letters+10digits+12special characters=48 options

i) For the first letter of the password there are 48 options.

For the second letter of the password there are 48 options.

For the third letter of the password there are 48 options.

For the fourth letter of the password there are 48 options.

For the fifth letter of the password there are 48 options.

For the sixth letter of the password there are 48 options.

For the seventh letter of the password there are 48 options.

For the eighth letter of the password there are 48 options.

To get the number of the possible usernames we multiply the number of options for each letter: 48 x 48 x 48 x 48 x 48 x 48 x 48 x 48= 48^8=28179280429056

ii)  If letter cannot be repeated.

For the first letter of the password there are 48 options.

For the second letter of the password there are only 47 options.

For the third letter of the password there are only 46 options.

For the fourth letter of the password there are only 45 options.

For the fifth letter of the password there are only 44 options.

For the sixth letter of the password there are only 43 options.

For the seventh letter of the password there are only 42 options.

For the eighth letter of the password there are only 41 options.

To get the number of the possible usernames we multiply the number of options for each letter: 48 x 47 x 46 x 45 x 44 x 43 x 42 x 41 =15214711438080

c) 26 uppercase letters+26 lowercase letters +10digits+12special characters=74 options

i) For the first letter of the password there are 74 options.

For the second letter of the password there are 74 options.

For the third letter of the password there are 74 options.

For the fourth letter of the password there are 74 options.

For the fifth letter of the password there are 74 options.

For the sixth letter of the password there are 74 options.

For the seventh letter of the password there are 74 options.

For the eighth letter of the password there are 74 options.

To get the number of the possible usernames we multiply the number of options for each letter: 74 x 74 x 74 x 74 x 74 x 74 x 74 x 74 =74^8=899194740203776

ii) If letter cannot be repeated.

For the first letter of the password there are 74 options.

For the second letter of the password there are only 73 options.

For the third letter of the password there are only 72 options.

For the fourth letter of the password there are only 71 options.

For the fifth letter of the password there are only 70 options.

For the sixth letter of the password there are only 69 options.

For the seventh letter of the password there are only 68 options.

For the eighth letter of the password there are only 67 options.

To get the number of the possible usernames we multiply the number of options for each letter: 74 x 73 x 72 x 71 x 70 x 69 x 68 x 67 =607681858331520

7 0
3 years ago
Quinton volunteers a the local hospital. He must distribute 5 trays of food to 12 rooms write and solve an equation to find how
allsm [11]

Answer:

60

Step-by-step explanation:

since we are taking 5 trys to each room and there are 12 you would multiply 5 by 12 making it 16

8 0
3 years ago
Read 2 more answers
For each mile that Jason runs, Megan runs 1\4 mile farther.If Jason ran 6 miles, how far did Megan run
Rom4ik [11]
Jason -1 mile
Megan - 1 mile + 1/4 mile = 1.25 mile

Jason - 6 miles
Megan - 6*1.25 = 7.5 miles


4 0
4 years ago
Read 2 more answers
A phone company offers two monthly plans. Plan A costs $11 plus an additional $0.11 for each minute of calls. Plan B costs $27 p
irina1246 [14]

Solution:

Let x represent a number of calling minutes. According to the problem, we want:

11\text{ + 0.11 x = }27\text{ + 0.07 x}

now, putting the similar terms together, we obtain:

0.11\text{ x - 0.07 x = 27 -11 }

this is equivalent to:

0.04x\text{ = 16}

now, solving for x, we get:

x\text{ = }\frac{16}{0.04}\text{ = 400}

then, the correct answer for the first question is:

400 minutes is the number of minutes the two plans cost the same

now, for the second question, we can replace the above value (400 minutes) into the following equation:

11\text{ + 0.11(400) = }55

so that, the correct answer for the second question is:

$55 is the cost when the two plans cost the same

3 0
1 year ago
There were 32 butterflies in the butterfly exhibit at the zoo. After some new butterflies hatched from their cocoons, there were
BigorU [14]
B and a

hope this helps!
3 0
3 years ago
Read 2 more answers
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