All categories

3 years ago

What is the solution to this system of equations?

Mathematics

1 answer:

mihalych1998 [28]3 years ago

5 0

Answer:

(0, -5)

Step-by-step explanation:

Multiply both sides of the second equation by 6 to get 6y=3x+30. Then, subtract the second equation from the first to cancel out the x's. y-6y=-5y, 3x-5-3x-30=-25. -5y=-25, so y=-5. Substitute -5 into the first equation to get 3x-5=-5, add five to both sides: 3x=0, divide by 3: x=0. The ordered pair is (0, -5). Hope this is correct and helps! :)

You might be interested in

What fraction is equivalent to the decimal and percent below? Enter your

Anna11 [10]

Answer: 1/2

Step-by-step explanation:

6 0

3 years ago

F(x) = - 2x<br> g(x) = 8x^2– 5x+7<br> Find (f .g)(x).

N76 [4]

Answer:

$\large\boxed{(f\cdot g)(x)=-16x^3+10x^2-14x}$

Step-by-step explanation:

$f(x)=-2x\\\\g(x)=8x^2-5x+7\\\\(f\cdot g)(x)=f(x)\cdot g(x)\\\\\text{substitute:}\\\\(f\cdot g)(x)=(-2x)(8x^2-5x+7)\qquad\text{use the distributive property}\\\\(f\cdot g)(x)=(-2x)(8x^2)+(-2x)(-5x)+(-2x)(7)\\\\(f\cdot g)(x)=-16x^3+10x^2-14x$

7 0

4 years ago

The expression 3t gives the number of tickets a player wins if he shoots the ball in the hoop t times. How many tickets would a

kari74 [83]

Answer: 48 tickets

Step-by-step explanation:

Since the expression that gives the number of tickets a player wins if he shoots the ball in the hoop t times is expressed as 3t.

Therefore, the number of tickets that a player wins if he shoots the ball in the hoop 16 times will be:

= 3t

where,

t = 16

Therefore, 3t = 3 × 16 = 48

The player wins 48 tickets.

3 0

3 years ago

A cell phone plan charges a monthly fee of $35 plus $0.05 per minute. Another company does not charge a monthly fee but charges

ehidna [41]

Answer:

it would be 375 minutes

Step-by-step explanation:

7 0

3 years ago

In a rotation what is the relationship between the distance from a point on the point on the preimage to the center of a rotatio

labwork [276]

Answer:

B. same distance

There is the same distance between the point on the preimage to the center of rotation and that of the distance from the corresponding point on the image to the center of rotation. There is change in the distance of the two.

Step-by-step explanation:

6 0

3 years ago

What is the solution to this system of equations?​

What is the solution to this system of equations?