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Paraphin [41]
3 years ago
5

What is the solution to this system of equations?​

Mathematics
1 answer:
mihalych1998 [28]3 years ago
5 0

Answer:

(0, -5)

Step-by-step explanation:

Multiply both sides of the second equation by 6 to get 6y=3x+30. Then, subtract the second equation from the first to cancel out the x's. y-6y=-5y, 3x-5-3x-30=-25. -5y=-25, so y=-5. Substitute -5 into the first equation to get 3x-5=-5, add five to both sides: 3x=0, divide by 3: x=0. The ordered pair is (0, -5). Hope this is correct and helps! :)

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I need help with the first one please someone help I don’t get it!
levacccp [35]

Answer:

2.2

Step-by-step explanation:

3 0
3 years ago
Eva has £6.05 in her moneybox.
PIT_PIT [208]

Answer:

11 of 20p, 22 of 10p and 33 of 5p

Step-by-step explanation:

Eva has 20p, 10p and 5p coins, total of £6.05 = 605p

Let 20p=x, 10p=y, 5p=z

<u>Then</u>:

  • 20x + 10y + 5z = 605
  • y : x = 2 : 1 ⇒ x= y/2
  • y : z = 2 : 3 ⇒ z= 3y/2

<u>Rewriting the first equation considering next two:</u>

  • 10y + 10y + 7.5y = 605
  • 27.5y = 605
  • y= 605/27.5
  • y= 22
  • x= y/2 = 22/2 = 11
  • z = 3y/2 = 3*11 = 33

<u>Answer:</u> 11 of 20p coins, 22 of 10p coins and 33 of 5p coins

3 0
3 years ago
What is 1/5 + 1/4 + 1/10
ivolga24 [154]

Answer:0.55

Step-by-step explanation:

1/5 + 1/4 + 1/10

add them all together

adds up to 0.55

8 0
3 years ago
Read 2 more answers
David earns $11 an hour. He was scheduled to work 35 hours. However, he picked up an additional 7 hour shift. He is paid double
zhenek [66]
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João gosta muito de animais de estimação e de charadas. Certo dia um amigo perguntou-lhe quantos cachorros e quantos gatos ele t
anastassius [24]

Responda:

a) 3 e 4

Explicação passo a passo:

Deixei :

Número de cães = x

Número de gatos = y

2x + 3y = 17 - - - - (1)

x - y = 1 - - - - (2)

De (2)

x = 1 + y

Coloque em (1)

2 (1 + y) + 3y = 17

2 + 2y + 3y = 17

2 + 5y = 17

5y = 17 - 2

5y = 15

y = 15/5

y = 3

x = 1 + y

x = 1 + 3

x = 4

Número de cães = x = 4

Número de gatos = y = 3

3 0
3 years ago
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