Answer:

Step-by-step explanation:
Hi!
Lets call:
T = temprature of the object
T₀ = temperature of surroundings
t = time
The rate of change of T is its derivative with respecto to time. If T > T₀, the object looses heat, so T decreases. Then, being k > 0:

In this case T₀ = 70ºF and k = 0.05/min. Then the differential equation is:

Use Photomath it graphs too
Answer:
DISTANCE=RATE*TIME. THEREFORE
X=3.6*1/6+4.2*1/6 (1/6 HOUR=10 MIN)
X=.6+.7
X=1.3 KM IS HOW FAR THEY WIL BE APART AFTER 10 MINUTES.
Step-by-step explanation: