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siniylev [52]
2 years ago
15

6. This solid is a composite of a cube and square pyramid. The base of the solid is the base of the cube. Find the surface area

for the solid​

Mathematics
1 answer:
Sergio039 [100]2 years ago
3 0

Answer:

960 ft^2

Step-by-step explanation:

There are 9 surfaces forming the solid.

5 of them are congruent squares and 4 of them are congruent triangles.

area of square = (side)^2

area of triangle = (base)(height)/2

total surface area = 5 * area of square + 4 * area of triangle

A = 5 * (12 ft)^2 + 4 * (12 ft * 10 ft)/2

A = 5 * 144 ft^2 + 4 * 60 ft^2

A = 720 ft^2 + 240 ft^2

A = 960 ft^2

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Answer:

The answer is;

54.4

Step-by-step explanation:

The given parameter are;

Triangle ΔFGH = Right triangle

The length of segment \overline {FH} = 48

The measure of ∠HFG = 28°

The measurement required = The measure of segment \overline {FG} = x

The measure of ∠FHG = 90° angle opposite hypotenuse side of a right triangle

Therefore, ∠FGH = 180° - ∠HFG - ∠FHG = 180° - 90° - 28° = 62°

∠FGH = 62°

By sine rule, we have;

\overline {FH}/(sin ∠FGH) = \overline {FG}/(sin(∠FHG)

By substituting the known values, we have;

48/(sin 62°) = x/(sin(90°)

sin(90°) = 1, therefore, we have;

x/1 = x = 48/(sin 62°) = 54.4 (by rounding the answer to the nearest tenth)

x = 54.4

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VashaNatasha [74]

Answer:

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Step-by-step explanation:

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