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siniylev [52]
3 years ago
15

6. This solid is a composite of a cube and square pyramid. The base of the solid is the base of the cube. Find the surface area

for the solid​

Mathematics
1 answer:
Sergio039 [100]3 years ago
3 0

Answer:

960 ft^2

Step-by-step explanation:

There are 9 surfaces forming the solid.

5 of them are congruent squares and 4 of them are congruent triangles.

area of square = (side)^2

area of triangle = (base)(height)/2

total surface area = 5 * area of square + 4 * area of triangle

A = 5 * (12 ft)^2 + 4 * (12 ft * 10 ft)/2

A = 5 * 144 ft^2 + 4 * 60 ft^2

A = 720 ft^2 + 240 ft^2

A = 960 ft^2

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Answer:

y=\frac{4}{5}e^{t}-\frac{4}{5}e^{-\frac{2}{5}t}

Step-by-step explanation:

The given equation 5y'' + 3y' - 2y =0 can be written as

(5D^{2}+3D-2)y(t)=0

Solving for complementary function we have Roots of (5D^{2}+3D-2) as follows

(5D^{2}+5D-2D-2)

5D(D+1)-2(D+1)=0\\\\(5D-2)(D+1)=0\\\\\therefore D=-1\\D=+2/5

Thus the complementary function becomes

y=y=c_{1}e^{m_{1}t}+c_{2}e^{m_{2}t}

where

m_{1},m_{2} are calculated roots

thus solution becomes

y=c_{1}e^{-t}+c_{2}e^{\frac{2}{5}t}

Now to solve for the coefficients we use the given boundary conditions

y(0)=0\\\\\therefore c_{1}+c_{2}=0\\\\y'(0)=-c_{1}+\frac{2}{5}c_{2}=2.8\\\\\therefore c_{2}+\frac{2}{5}c_{2}=2.8\\\\c_{2}=2\\\\\therefore c_{1}=-2}

hence the solution becomes

y=-2e^-{t}+2e^{\frac{2}{5}t}

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