Answer:

Step-by-step explanation:
The given equation 5y'' + 3y' - 2y =0 can be written as

Solving for complementary function we have Roots of
as follows


Thus the complementary function becomes
y=
where
are calculated roots
thus solution becomes

Now to solve for the coefficients we use the given boundary conditions

hence the solution becomes

Separate into two inequalities.
1x < 3
1x > -15
Solve for x.
x < 3
x > -15
Sin 2θ = sin θ
2sin θ cos θ = sin θ
2cos θ = 1
cos θ = 1/2
θ = arccos(1/2) = 60° and 300°
θ = 60° and 300°