V = lwh
2x³ + 17x² + 46x + 40 = l(x + 4)(x + 2)
2x³ + 12x² + 16x + 5x² + 30x + 40 = l(x + 4)(x + 2)
2x(x²) + 2x(6x) + 2x(8) + 5(x²) + 5(6x) + 5(8) = l(x + 4)(x + 2)
2x(x² + 6x + 8) + 5(x² + 6x + 8) = l(x + 4)(x + 2)
(2x + 5)(x² + 6x + 8) = l(x + 2)(x + 4)
(2x + 5)(x² + 2x + 4x + 8) = l(x + 4)(x + 2)
(2x + 5)(x(x) + x(2) + 4(x) + 4(2)) = l(x + 4)(x + 2)
(2x + 5)(x(x + 2) + 4(x + 2)) = l(x + 4)(x + 2)
(2x + 5)(x + 4)(x + 2) = l(x + 4)(x + 2)
(x + 4)(x + 2) (x + 4)(x + 2)
2x + 5 = l
17
it's 17+(-7)=10
i hope that answers your problem
They are similar because of the color and they are different by the size and shape hope that helps you
Answer:
13,67,29,17,19,23
Step-by-step explanation:
Answer:
The augmented matrix of the system is
.
We apply operations rows:
1. We swap row 1 and 2 and obtain the matrix
.
2. Of the above matrix we subtract row 1 from row 2 twice (R2 - 2R1) and we subtract row 1 from row 3, 5 times. (R3-5R1). We obtain the matrix ![\left[\begin{array}{cccc}1&2&1&4\\0&-1&-3&6\\0&-1&-3&-13\end{array}\right]](https://tex.z-dn.net/?f=%5Cleft%5B%5Cbegin%7Barray%7D%7Bcccc%7D1%262%261%264%5C%5C0%26-1%26-3%266%5C%5C0%26-1%26-3%26-13%5Cend%7Barray%7D%5Cright%5D)
3. Of the above matrix we subtract row 2 from row1 twice (R3 - R2) and multiply the row 1 by -1 (-R2). Weobtain the matrix
.
Since each pivote is an one then we conclude that the above matrix is the reduced row-echelon form of the matrix of the system.