Write the pair of fractions as a pair of fractions with a common denominator.
2 answers:
You might be interested in
So,
#1:
Convert to like improper fractions.
Add.
So, one solution could be
.
Another solution could by 9. There is also 10, 11, 12, etc., and all numbers in between.
#2:
Convert into improper fraction form.
Multiply.
Cross-cancel, and we have our final result.
k < 96
96 is not a solution.
95 is a solution.
So is 94, 93, 92, etc, and all numbers in between.
#1:
Convert to like improper fractions.
Add.
So, one solution could be
Another solution could by 9. There is also 10, 11, 12, etc., and all numbers in between.
#2:
Convert into improper fraction form.
Multiply.
Cross-cancel, and we have our final result.
k < 96
96 is not a solution.
95 is a solution.
So is 94, 93, 92, etc, and all numbers in between.
You would expand becausee it isn't equal to anything
(x+3)^3=(x+3)(x+3)(x+3)
we can use binomial theorem or pascal's triangle
anyway, pascal's triangle is more practicl for this one
so
for the 3rd power
a=x
b=3
=
(x+3)^3=(x+3)(x+3)(x+3)
we can use binomial theorem or pascal's triangle
anyway, pascal's triangle is more practicl for this one
so
for the 3rd power
a=x
b=3