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Kipish [7]
3 years ago
8

The dimensions of a rectangular pool table are: (x + 4)(x + 10), What is the area of the table?

Mathematics
2 answers:
sergij07 [2.7K]3 years ago
6 0

Answer:

D. x^2 +14x + 40

Step-by-step explanation:

(x+4)(x+10)

x^2+10x+4x+40

x^2+14x+40

Anastasy [175]3 years ago
5 0

Answer:

d) x^2+14x+40

Step-by-step explanation:

You gotta multiply (x + 4)(x + 10)

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Calculate the area shaded
Rudiy27

Answer:

7.722 cm^2

Step-by-step explanation:

Step 1: Find the area of the square.

  • Area of square = s^2, where s = side
  • 6^2 = 36 cm^2

Step 2: Find the area of the circle.

  • We are given the diameter of the circle as 6 cm, so the radius must be 3 cm.
  • Area of circle is \pi r^2, so now we plug in and simplify.
  • 3.142 * 3^2
  • 3.142 * 9
  • 28.278

Step 3: Subtract area of circle from area of square.

  • 36 - 28.278
  • 7.722

Therefore, the area of the shaded region is 7.722 cm^2.

Have a lovely rest of your day/night, and good luck with your assignments! ♡

6 0
2 years ago
What would you rather earn a 1 million dollars a day or a 1 dollar a day and it doubles every day?
larisa86 [58]

1 millions because the I wold get more and then 1 dollar a day and double will give me less

7 0
3 years ago
Read 2 more answers
24 pencils cost $1.20, how much will one pencil cost?
Serggg [28]

Answer:

1) $0.05

2) $5.00

Step-by-step explanation:

1)

1.2/24 = 0.05

2)

22.5/4.5 = 5

7 0
2 years ago
Find the zeros (roots) of the following equations. f(x) = 2x5 - 9x4 + 12x3 - 12x2 + 10x - 3 = 0
Talja [164]
Hi,
f(1)=2*1^5-9*1^4+12*1^3-12*1^2+10*1-3\\
=2-9+12-12+10-3\\
=0\\

f(x)=(x-1)(2x^4-7x^3+5x^2-7x+3)\\


g(x)=2x^4-7x^3+5x^2-7x+3\\

g(3)=2*3^4-7*3^3+5*3^2-7*3+3\\
=162-189+45-21+3\\
=0\\

g(x)=(x-3)(2x^3-x^2+2x-1)\\

h(x)=2x^3-x^2+2x-1\\

h( \dfrac{1}{2} )=2* \dfrac{1}{8} - \dfrac{1} {4}+1-1\\
=0\\

h(x)=(2x-1)(x^2+1)\\


f(x)=(x-1)(x-3)(2x-1)(x+i)(x-i)\\



Roots are 1,3,0.5,i,-i.

8 0
3 years ago
Need help with functions
Komok [63]

Answer: ur right

Step-by-step explanation:

4 0
2 years ago
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