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Kipish [7]
3 years ago
8

The dimensions of a rectangular pool table are: (x + 4)(x + 10), What is the area of the table?

Mathematics
2 answers:
sergij07 [2.7K]3 years ago
6 0

Answer:

D. x^2 +14x + 40

Step-by-step explanation:

(x+4)(x+10)

x^2+10x+4x+40

x^2+14x+40

Anastasy [175]3 years ago
5 0

Answer:

d) x^2+14x+40

Step-by-step explanation:

You gotta multiply (x + 4)(x + 10)

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inn [45]
There is no solution to this system of equations because they both have the same slope.

If two lines have the same slope, but are not identically the same line, then they will never intersect. There is no pair (x, y) that could satisfy both equations, because there is no point (x, y) that is simultaneously on both lines. Therefore, these equations are said to be inconsistent, and there is no solution.
5 0
3 years ago
7. The bake sale raised $100. If each candy sold cost $0.50, how many candies were sold?​
ZanzabumX [31]

Answer:

200 candies were sold

Step-by-step explanation:

Because we know that each candy costs $0.50, we can simply divide 100 by 0.5.

100/0.5\\200

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3 years ago
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Each measure.
Novosadov [1.4K]

Answer A

Step-by-step explanation:

A

5 0
3 years ago
CAN SOMEBODY HELP ME PLEASE AND THANK YOU!​
Dafna1 [17]

Hello! To do this, first find the volumes of the tanks (how much water they can hold), then how much water is in tank P, and finally, how full tank Q would be.

----

To find the volume of a rectangular prism, you multiply the length, width, and height.

Tank P:  15 * 12 * 8 = 1440 cm³

Tank Q:  10 * 20 * 6 = 1200 cm³

Now, we know that tank P is half full. Therefore, the volume of the water must be half that of the whole volume of tank P. We know the volume of Tank P is 1440 cm³, so just divide by 2.

1440/2 = 720 cm³

Therefore, there is 720 cm³ amount of water in Tank P. Finally, find how much of Tank Q this amount of water would occupy.

Set up a fraction to do this:

720 / 1200 = 0.6 = 3/5

----

Therefore, 3/5 of Tank Q is filled.

Hope this helps!

4 0
3 years ago
This week, we are covering relationships that can be approximated by linear equations. For instance, y = 453x + 3768 represents
lana [24]

Answer:

See explanation below.

Step-by-step explanation:

We assume that the data is given by :

x: 30, 30, 30, 50, 50, 50, 70,70, 70,90,90,90

y: 38, 43, 29, 32, 26, 33, 19, 27, 23, 14, 19, 21.

Where X represent the cost for scholarships in thousands of dollars and y represent the cost of life for an academic semester (The data comes from the web)

We can find the least-squares line appropriate for this data.  

For this case we need to calculate the slope with the following formula:

m=\frac{S_{xy}}{S_{xx}}

Where:

S_{xy}=\sum_{i=1}^n x_i y_i -\frac{(\sum_{i=1}^n x_i)(\sum_{i=1}^n y_i)}{n}

S_{xx}=\sum_{i=1}^n x^2_i -\frac{(\sum_{i=1}^n x_i)^2}{n}

So we can find the sums like this:

\sum_{i=1}^n x_i = 30+30+30+50+50+50+70+70+70+90+90+90=720

\sum_{i=1}^n y_i =38+43+29+32+26+33+19+27+23+14+19+21=324

\sum_{i=1}^n x^2_i =30^2+30^2+30^2+50^2+50^2+50^2+70^2+70^2+70^2+90^2+90^2+90^2=49200

\sum_{i=1}^n y^2_i =38^2+43^2+29^2+32^2+26^2+33^2+19^2+27^2+23^2+14^2+19^2+21^2=9540

\sum_{i=1}^n x_i y_i =30*38+30*43+30*29+50*32+50*26+50*33+70*19+70*27+70*23+90*14+90*19+90*21=17540

With these we can find the sums:

S_{xx}=\sum_{i=1}^n x^2_i -\frac{(\sum_{i=1}^n x_i)^2}{n}=49200-\frac{720^2}{12}=6000

S_{xy}=\sum_{i=1}^n x_i y_i -\frac{(\sum_{i=1}^n x_i)(\sum_{i=1}^n y_i)}=17540-\frac{720*324}{12}{12}=-1900

And the slope would be:

m=-\frac{1900}{6000}=-0.317

Nowe we can find the means for x and y like this:

\bar x= \frac{\sum x_i}{n}=\frac{720}{12}=60

\bar y= \frac{\sum y_i}{n}=\frac{324}{12}=27

And we can find the intercept using this:

b=\bar y -m \bar x=27-(-0.317*60)=46.02

So the line would be given by:

y=-0.317 x +46.02

We have an inverse linear relationship since the slope is negative between the variables of interest.

8 0
4 years ago
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