A and b can do a piece of work in 12 days. If a alone have to finish the job among b and c so
A and b=12
A (24 days alone without b)
So if b and c 15 days and c 20 days. If a have to do all I would add 24 and 15 and 20 which would be 59 days
C is the answer ... all u has to do was subtract 5 from 12 , then -11-14 , then -13-9
Answer:
Third option
Step-by-step explanation:
Because it has to be JKL or LKJ, (see how the K stays in the middle)
Answer: False
Systems of linear equations can only have 0, 1, or an infinite number of solutions. These two lines cannot intersect twice. The correct answer is that the system has one solution.
Step-by-step explanation:
