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gulaghasi [49]
3 years ago
6

How do i solve 5x-9y=-17 and 5x+3y=19 in elimation

Mathematics
1 answer:
Mkey [24]3 years ago
8 0
<span>A) 5x -9y = -17
B) 5x +3y = 19
If we multiply equation A by -1
</span>
<span>A) -5x +9y = 17 then add it to B)
</span><span>B) 5x +3y = 19
12y = 36
y = 3
we have eliminated the "x" term.

</span>
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How many students must be randomly selected to estimate the mean weekly earnings of students at one college? We want 95% confide
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Answer:

The sample of students required to estimate the mean weekly earnings of students at one college is of size, 3458.

Step-by-step explanation:

The (1 - <em>α</em>)% confidence interval for population mean (<em>μ</em>) is:

CI=\bar x\pm z_{\alpha/2}\times \frac{\sigma}{\sqrt{n}}

The margin of error of a (1 - <em>α</em>)% confidence interval for population mean (<em>μ</em>) is:

MOE=z_{\alpha/2}\times \frac{\sigma}{\sqrt{n}}

The information provided is:

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The critical value of <em>z</em> for 95% confidence level is:

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Compute the sample size as follows:

MOE=z_{\alpha/2}\times \frac{\sigma}{\sqrt{n}}

       n=[\frac{z_{\alpha/2}\times \sigma }{MOE}]^{2}

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          =3457.44\\\approx 3458

Thus, the sample of students required to estimate the mean weekly earnings of students at one college is of size, 3458.

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