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2 years ago

Calculate the area of the shaded region between the regular polygons. Round to the nearest hundredth.

Mathematics

1 answer:

wolverine [178]2 years ago

3 0

Answer:

I hope I'll help you with this but I am not sure of it all...

The area of the shaded region is 46,77

Step-by-step explanation:

To determine the area of the shaded hexagon, we must first calculate te area of the whole shaded hexagon and minus that by the white little hexagon.

The formula to calculate the area of a hexagon is (3√3 s2)/ 2

(where s = one side of the hexagon)

if one side a the little white hexagon equals 6 ft;

3√3 6ft.2/2 = 18√3/2 = 9√3

now for the bigger hexagon where one side is 12 ft;

3√3 12 ft.2/2 = 72√3/2 = 36√3

now the area of the bigger one minus the area of the smaller one;

36√3 - 9√3 = 46,77

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A right-angled triangle has shorter side lengths exactly c^2-b^2 and 2bc units respectively, where b and c are positive real num

yKpoI14uk [10]

Answer: hypotenuse = $c^{2} + b^{2}$

Step-by-step explanation: Pythagorean theorem states that square of hypotenuse (h) equals the sum of squares of each side ( $s_{1},s_{2}$ ) of the right triangle, .i.e.:

$h^{2} = s_{1}^{2} + s_{2}^{2}$

In this question:

$s_{1}$ = $c^{2}-b^{2}$

$s_{2} =$ 2bc

Substituing and taking square root to find hypotenuse:

$h=\sqrt{(c^{2}-b^{2})^{2}+(2bc)^{2}}$

Calculating:

$h=\sqrt{c^{4}+b^{4}-2b^{2}c^{2}+(4b^{2}c^{2})}$

$h=\sqrt{c^{4}+b^{4}+2b^{2}c^{2}}$

$c^{4}+b^{4}+2b^{2}c^{2}$ = $(c^{2}+b^{2})^{2}$ , then:

$h=\sqrt{(c^{2}+b^{2})^{2}}$

$h=(c^{2}+b^{2})$

Hypotenuse for the right-angled triangle is $h=(c^{2}+b^{2})$ units

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3 years ago

5 consecutive integers whose sum is -155

nekit [7.7K]

Answer:

-29, -30, -31, -32, -33

Step-by-step explanation:

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3 years ago

In how many different ways can a red, blue, and green marker be arranged in a tray?

grigory [225]

Answer:

6 ways.

There are one red, one blue and one green maker. So there are 3 markers they are in 3! = 3×2 = 6 ways.

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3 years ago

1. Which of the following is the equation of a line that has a slope 5 and passes through the point

kondaur [170]

Answer:

Hope this helps!

Step-by-step explanation:

4 0

3 years ago

Read 2 more answers

PLS Help me Error Analysis

Maksim231197 [3]

we have

<u>Pieces of mail delivered in December by the US postal service</u>

$7.14*10^{10}$

<u>Pieces of mail delivered in January by the US postal service</u>

$3.21*10^{10}$

To find the total mail delivered for these two months, sum the two quantities

$7.14*10^{10}+3.21*10^{10}=(7.14+3.21)*10^{10}\\=10.35*10^{10} \\=(1.035*10)*10^{10} \\=1.035*(10* 10^{10})\\=1.035*10^{(10+1)} \\= 1.035*10^{11}$

therefore

the correct solution is $1.035*10^{11}$

the error is in this part

$10.35*10^{10}$

To move decimal over one place 10 to the power of 10 should be 10 to the power of 11

$1.035*10^{10}$

3 0

3 years ago