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Georgia [21]
3 years ago
11

What is the area of the triangle?

Mathematics
1 answer:
Agata [3.3K]3 years ago
7 0

Answer:

168 is the answer

Step-by-step explanation:

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2 less than five times a number.
Reika [66]

Answer:

X will be the number.  

5 times that number X is 5X

2 less than 5 times the number is 5X - 2

Hope this helps! Plz mark brainliest! (づ ̄3 ̄)づ╭❤~

8 0
3 years ago
Read 2 more answers
Quadrilateral ABCD is a parallelogram. Given this, fill in the coordinates below.
Lubov Fominskaja [6]

Answer:

The coordinates of D are (8,3)

Step-by-step explanation:

We have quadrilateral ABCD being a parallelogram with coordinates A(3,2), B(5,4), C(10,5), and D(a,b).

We want to find the coordinates of D.

Since ABCD is a parallelogram, the diagonals AC and BD bisects each other.

The midpoint of AC is (13/2,7/2).

This is also the midpoint of BD.

By the midpoint rule:

( \frac{5 + a}{2} , \frac{4 + b}{2} ) = ( \frac{13}{2} , \frac{7}{2} )

This implies that:

5 + a = 13 \\ a = 13 - 5 \\ a = 8

Similarly,

4 + b = 7 \\ b = 7 - 4 \\ b = 3

The coordinates of D are (8,3)

8 0
3 years ago
The base and height of a parallelogram are in the ratio of 6:5. It's area is 480 inches squared. Find the height of the parallel
lara [203]

Answer:

The height of the parallelogram is 20m

Step-by-step explanation:

Given the area of a parallelogram

A = bh where;

b is the base and h is the height

If the base and height of a parallelogram are in the ratio of 6:5. It's area is 480 inches, this means that b/h = 6/5

5b = 6h

b = 6h/5

Substituting equation 1 into the volume if the parallelogram we have;

A = 6h/5×h

480 = 6h²/5

6h² = 480×5

6h² = 2400

h² = 2400/6

h² = 400

h = √400

h = 20m

3 0
3 years ago
I don’t know this one <br> I need help
Marysya12 [62]
Sorry I don’t know I would help you tho
4 0
3 years ago
(1 point) Suppose that water is pouring into a swimming pool in the shape of a right circular cylinder at a constant rate of 6 c
skad [1K]

Answer:

dh/dt = 2/3*π  ft/min

Step-by-step explanation:

We have a right circular cylinder, and water is pouring at a constant rate, we must expect the height  of the water will rise a constant rate, therefore it does not matter the height

V(c) = π*r²*h     ⇒  V(c) = π*(3)²*h  ⇒ V(c) =9*π*h

DV(c)/dh  =  9*π

DV(c)/dh = DV(c)/dt  *  dt/ dh    ⇒   9*π  =   DV(c)/dt  *  dt/ dh  

dh/dt  =   DV(c)/dt /  9*π

DV(c)/dt  = 6 ft³/m     ( from problem statement )

Then

dh/dt = 6/9*π ft/min

dh/dt = 2/3*π  ft/min

5 0
3 years ago
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