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Harman [31]
3 years ago
11

Gianna brought seven necklaces for $50.75 and Winnie brought three necklaces for $24.60 who got the better deal

Mathematics
1 answer:
olganol [36]3 years ago
4 0
Gianna paid less per necklace so she got the better deal

Gianna: 50.75 / 7 = 7.25
So she paid $7.25 per necklace
Winnie: 24.60 / 3 = 8.20
So she paid $8.20 per necklace

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8 copies of the sum of 4 thirds and 2 more? (Show your work)
KengaRu [80]

Answer:

40

Step-by-step explanation:

8copies of sum 4/3 and 2

So let's solve

Sum of 4/3and 2

4/3+2

Lcm is 3

4+6/2

10/2

5

8copies means 8 multiply by the sum of 4/3 and 2

So 8(5)

=40

So the answer is 40

6 0
3 years ago
HELPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPP
sergejj [24]

Answer:

just  relax take ur time and breath or just look it up

Step-by-step explanation:

inhale

exhale  

you got this my friand

6 0
2 years ago
Read 2 more answers
Last year there were k pies baked in the bake sale. This year, there were 187 pies baked. Using k, write an expression of the to
Shkiper50 [21]

Answer:

d

Step-by-step explanation:

4 0
3 years ago
SEE ATTACHED
fenix001 [56]
To me personally, the first bit f(g(x)) is easy and the domain is tricky. Let's try explain this.

A function takes an input number and returns an output number depending on the function. Look at f(x) = x+3, if we let the input number be 2 then we say that f(2) = 5. We could do f(π) to give us π+3 or even f(x²) to give us x² +3. The trick is to substitute the input into the function equation.

You have been asked to find f(g(x)). You know f(x) = \frac{1+x}{1-x}. Putting numbers in at this point would be easy (try work out f(2), you'll do it really quick) but you have to put in g(x).

f(g(x)) = \frac{1+g(x)}{1-g(x)}
we also know that g(x) = \frac{x}{1-x} so we can say that
f(g(x)) = \frac{1+ \frac{x}{1-x} }{1- \frac{x}{1-x} } and that is f(g(x)) but the question requires that we simplify it so
\frac{1+ \frac{x}{1-x} }{1- \frac{x}{1-x} }  =  \frac{ \frac{1-x}{1-x} +  \frac{x}{1-x} }{ \frac{1-x}{1-x} - \frac{x}{1-x} } =  \frac{ \frac{1}{1-x} }{ \frac{1-2x}{1-x} } =  \frac{1}{1-2x}

f(g(x)) = \frac{1}{1-2x}

Now for the tricky bit (for me, at least). The domain is the full set of values that you can 'put in to' the function and still get a real value out. So how do we work out what numbers 'break' the function? I like to use the fact that DIVIDING BY ZERO IS IMPOSSIBLE. What value of x can we put into the function to make it so the function is being divided by 0? i.e. 1-2x = 0 solve that and you have a value of x that isn't part of the domain.

This means the domain is all real numbers EXCEPT the solution to that equation. (Because if we put that value into f(g(x)) it's impossible to get a value out.)

[I know this was a lot to read, if you have any questions or don't get anything feel free to message me or leave a comment.]

5 0
3 years ago
X2 -2x -24=0 is equivalent to<br><br> Answer(S):
sergey [27]

Answer:

x= 6, -4

Step-by-step explanation:

x^2 - 2x - 24 = 0

(x-6) (x+4) = 0

x = 6, x= -4

4 0
2 years ago
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