<span>The sum of two numbers is 48.
a + b = 48
;
If one third of one number is 5 greater than one sixth of another number,
a = b + 5
multiply both sides by 6, cancel the fractions
2a = b + 30
2a - b = 30
</span><span>use elimination to solve this
a + b = 48
2a - b =30
-------------Addition eliminates b, find a
3a = 78
a =
a = 26
then
26 + b = 48
b = 48 - 26
b = 22</span>
10x(3x^2)
15x^2(2x)
5x(6x^2)
Answer:
CotR = -√3
Step-by-step explanation:
In the 4th quadrant, sin is negative;
Since Cos R = √3/2,
Adjacent = √3
Hypotenuse = 2
Get the opposite;
opp^2 = 2^2 -(√3)^2
opp^2 = 4 - 3
opp^2 = 1
Opp = 1
Get sinR
Sin R = opp/hyp
SinR= -1/2
CotR = cosR/sinR
CostR = (√3/2)/(-1/2)
CotR = √3/2* -2/1
CotR = -√3
4- adding because it’s the opposite
