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malfutka [58]
3 years ago
10

I need help ASAP!! Please explain how to solve the problem

Mathematics
1 answer:
a_sh-v [17]3 years ago
3 0

Answer:

Surface area=114 cm^2

Step-by-step explanation:

Surface area of a cuboid is given be 2(lb+bh+lh). ATQ, l=3, h=3, b=8. Plugging them into the formula, we will get surface area=114 cm^2

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-3.143 = -3140/999<br>True<br>False​
Neporo4naja [7]

Answer:

false

Step-by-step explanation:

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3 years ago
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Ok... FREE 100 POINTS WHOEVER ANSWERS FIRST WILL GET A BRAINLIEST!!!
n200080 [17]

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AHHH

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When rolling two standard six-sided dice, what is the probability that the sum of the dice will be even or a multiple of 3? (sho
aliya0001 [1]

Answer:

2/3

Step-by-step explanation:

List all the possible sums.  If it helps, make a table:

\left[\begin{array}{ccccccc} &1&2&3&4&5&6\\1&2&3&4&5&6&7\\2&3&4&5&6&7&8\\3&4&5&6&7&8&9\\4&5&6&7&8&9&10\\5&6&7&8&9&10&11\\6&7&8&9&10&11&12\end{array}\right]

There are 36 total possible sums.  Of those, 18 are even, and 6 are odd but multiples of 3.

Therefore, the probability is:

P = (18 + 6) / 36

P = 24 / 36

P = 2 / 3

8 0
4 years ago
The solution to -45= n/5 is
Andrew [12]

Answer:

n=5*-45

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Step-by-step explanation:

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4 years ago
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Someone get me the answers ASAP!! thank you
Virty [35]
This relies on the distance formula like number two, which you answered correctly.

I think it's helpful to draw this out. I made a digital drawing on GeoGebra (free) and connected the vertices. Now, to find the area, we need the side lengths to start. This program actually gives you the side lengths as well, but pretending we don't already have that, you can plug in each vertex into the distance formula.

a =  \sqrt{(-4-3)^{2}+ (2-2)^{2}} = 7

b =  \sqrt{(3-3)^{2}+(2-(-5))^{2}} = 7

c =  \sqrt{(3-(-4))^{2}+(-5-(-2))^{2}} =  \sqrt{58}

d =  \sqrt{(-4-(-4))^{2}+(2-(-2))^{2}} = 4

So, unfortunately, we don't have a regular polygon, so this isn't simply length times width. But we can easily cut this into a rectangle and a triangle, whose areas are much easier to find (see second image).

The area, A, of a triangle is \frac{1}{2} B * h and the area of a rectangle is simply l * w. So the base of our triangle is 7 units, and the height is 3 units, so the area is 10.5 units squared. The length of our rectangle is 7 units, and the width is 4 units, so the area is 28 units squared.

A = A_{triangle} + A_{rectangle} = 10 \frac{1}{2}+28 = 38\frac{1}{2} units squared.



I would like to clarify that you do not actually need to find all those distances for this problem. Once it's drawn out, it's fairly easy to tell.

7 0
4 years ago
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