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1 year ago

5

Una superficie mide 400 cm de largo y 360 cm de ancho. Se quiere dividir en cuadrados que tengan la mayor área posible y que la

medida de los lados sea un número natural. ¿Cuántos cuadrados habrá en el rectángulo?

1 answer:

victus00 [196]1 year ago

5 0

Answer:

https://scuolaelettrica.it/correttore/spagnolo/manutenzione/risolutore/risolti/risoltirettangolo.php

Step-by-step explanation:

here use this

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if you deposit 4500 at 5% annual interest compounded annually how much money will be in the account after 30 months

Alja [10]

Answer:

A = $ 50,978.44

Step-by-step explanation:

First, convert R percent to r a decimal

r = R/100

r = 5%/100

r = 0.05 per year,

Then, solve our equation for A

A = P(1 + r/n)nt

A = 45,000.00(1 + 0.004166667/12)(12)(2.5)

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2 years ago

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andrew-mc [135]

The square root of a prime number (11) is irrational

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2 years ago

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When a teacher divided her students into groups of four, she had three students remaining. when she divided them into groups of

AfilCa [17]

39 students....39/4 = 9 remainder 3
39/5 = 7 remainder 4

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2 years ago

What are the coordinates of the vertex?

faltersainse [42]

(-2,8) is the answer

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2 years ago

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Please Help Me! I will give all my point to who ever answers my question!!!

love history [14]

Step-by-step explanation:

The equation that is given is only for the specific place of that object. To find the velocity, you need to take the derivative of the equation. This will give you:

$V=2+\frac{1}{2} t$

Now, to find the average velocity of this object, plug in the values given to you. It's between the time interval [1, 2] so these are the two numbers you'll plug into the velocity equation. Finding this average is like finding any other average.

So

$V(1)=2+\frac{1}{2} (1)\\V(1)=2+\frac{1}{2}=\frac{5}{2}\\V(2)=2+\frac{1}{2}(2)\\V(2)=2+1=3$

$V_{avg}=\frac{3-\frac{5}{2} }{2-1} \\V_{avg}=\frac{\frac{6}{2}-\frac{5}{2} }{1} \\V_{avg}=\frac{1}{2}$

Average velocity is 0.5 sec

To find instantaneous velocity just find the velocity at time one. Think about the name "instantaneous velocity," it's the velocity in that <u>instant</u>.

We already found this, so I don't need more work (it's displayed above).

The instantaneous velocity when $t=1$ is 2.5 sec.

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2 years ago