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LenaWriter [7]
3 years ago
9

ayoo nye here i was useing this app for this work and this is what got that is not okay so if you just going to say hi or hello

then say that on somone else bc i am not about to be called dum slow on my life and if u dont know when dont say it i am not trying to get FFFFFFFFFFFFFFFFFF i want AAAAABBBBBCCCCC not FF and if you think im right then commet and if you dont say noooooooooo

Mathematics
2 answers:
Korvikt [17]3 years ago
8 0

Answer:

i belive you are right

Step-by-step explanation:

seraphim [82]3 years ago
4 0

Answer:

um yeah

Step-by-step explanation:

You might be interested in
In preparation for an earnings report, a large retailer wants to estimate p= the proportion of annual sales
mr Goodwill [35]

Using the z-distribution, it is found that the 95% confidence interval for the proportion of sales that occured in December is (0.1648, 0.2948).

<h3>What is a confidence interval of proportions?</h3>

A confidence interval of proportions is given by:

\pi \pm z\sqrt{\frac{\pi(1-\pi)}{n}}

In which:

  • \pi is the sample proportion.
  • z is the critical value.
  • n is the sample size.

In this problem, we have a 95% confidence level, hence\alpha = 0.95, z is the value of Z that has a p-value of \frac{1+0.95}{2} = 0.975, so the critical value is z = 1.96.

The sample size and the estimate are given by:

n = 161, \pi = \frac{37}{161} = 0.2298

Hence:

\pi - z\sqrt{\frac{\pi(1-\pi)}{n}} = 0.2298 - 1.96\sqrt{\frac{0.2298(0.7702)}{161}} = 0.1648

\pi + z\sqrt{\frac{\pi(1-\pi)}{n}} = 0.2298 + 1.96\sqrt{\frac{0.2298(0.7702)}{161}} = 0.2948

The 95% confidence interval for the proportion of sales that occured in December is (0.1648, 0.2948).

More can be learned about the z-distribution at brainly.com/question/25890103

5 0
2 years ago
In one year, three awards (research, teaching, and service) are given to a class of 25 graduate students in a statistics departm
allochka39001 [22]

Answer:

13,800

Step-by-step explanation:

This is a permutation, not a combination, because order matters.

Here's why:

Arbitrarily, let's say that the three students chosen for the award are Abby, Bob, and Charlie. The order of which each award is given to the three of them matters, because otherwise they would be receiving different awards. For example, if Abby gets the research award, Bob gets the teaching award, and Charlie gets the service award, this would be notably different than if Abby got the teaching award, Bob got the service award, and Charlie got the research award.

Therefore, for the first award, we have 25 people to choose from. After we select that person, we have 24 people to choose from, since the problem stipulates that each student can receive at most one award. Then 23, and so on.

Since we're choosing three people to give awards to, there are:

25\cdot 24\cdot 23=\boxed{13,800} permutations. Because order matters (refer to explanation above), this is our final answer.

3 0
3 years ago
If Acot theta + Bcot theta =4 and
geniusboy [140]

Answer is: B

Step-by-step explanation: correct answer is B

b  

2

−a  

2

 

Given, acotθ+bcscθ=p

           bcotθ+acscθ=q

⇒p  

2

−q  

2

=(p−q)(p+q)

                   =[acotθ+bcscθ−bcotθ−acscθ][acotθ+bcscθ+bcotθ+acscθ]

                   =[cotθ(a−b)−cscθ(a−b)][cotθ(a+b)+cscθ(a+b)]

                   =(a−b)(cotθ−cscθ)(a+b)(cotθ+cscθ)

                   =(a  

2

−b  

2

)(cot  

2

θ−csc  

2

θ)

                   =(−1)(a  

2

−b  

2

)[∵csc  

2

θ−cot  

2

θ=1]

                   =(b  

2

−a  

2

)

7 0
2 years ago
A sandbox is a right rectangular prism
horrorfan [7]
4.6 Is the answer I thinkkkkk
7 0
2 years ago
sarah is currently making 39,000 a year at her job and had been offered a raise to 43,290 per year what would be the percent inc
Ivan
43290-39000=4290
4290÷39000=0.11
0.11x100= 11% increase
8 0
3 years ago
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