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daser333 [38]
2 years ago
7

If it took eight men ten hours to build a wall, how many hours would it take four men to build it?

Mathematics
2 answers:
olga nikolaevna [1]2 years ago
8 0
8 men= 10hours
Now,
4men= ? hours

Since there are lesser number of men, the amount of time needed will be greater.. Thus, you need to multiply the amount of hours by 2! If you are thinking why, look at the following steps
8/2=4 (men)
10 x 2= 20(time)

Thus the answer is 20

Hope this helped :))
arlik [135]2 years ago
4 0
Two hours bc if it takes 8 to do it in one hour and u split the number of men u have in half you double the work hours 8men=1hour of work 4men=2hours of work
Hope this helps have a nice day
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Help please with these questions
sergeinik [125]

Answer:

1. There is a <u><em>1/5</em></u> chance you will get a blue one from both bags.

2. There is a <u><em>3/32</em></u> chance you will get a 1 and then a 2.

3. There is a <u><em>5/12</em></u> chance of rolling a factor of 12 and then an odd number.

Step-by-step explanation:

<u><em>Question 1</em></u>

Add all the marbles together.

3 + 2 = 5

4 + 2 = 6

Make a fraction.

blue/all

Use it on the numbers.

3/5

2/6

Multiply them together.

6/30

Simplify.

1/5

There is a <u><em>1/5</em></u> chance you will get a blue one from both bags.

<u><em>Question 2</em></u>

Add all the numbers together.

There are 8.

Make the two crucial fractions.

ones/all

twos/all

Use them.

3/8

2/8

Multiply them together.

6/64

Simplify.

3/32

There is a <u><em>3/32</em></u> chance you will get a 1 and then a 2.

<u><em>Question 3</em></u>

Find the factors of 12.

1, 2, 3, 4, 6

Make a fraction.

factors/all

Use the fraction.

5/6

Find the odd numbers.

1, 3, 5

Make a fraction.

odd/all

Use the fraction.

3/6

Multiply them together.

15/36

Simplify.

5/12

There is a <u><em>5/12</em></u> chance of rolling a factor of 12 and then an odd number.

8 0
2 years ago
An airplane flew for 8 hours at an airspeed of x miles per hour (mph), and for 7 more hours at 325 mph. If the average airspeed
Thepotemich [5.8K]
E. 8x+7(325)=15(325)

It would include the 8 hrs. of x miles per hour and the 7 hrs. of 325 miles per hour, giving the total miles. Then, as you eliminate, you can find out what (x) is.
4 0
3 years ago
What is 73×28 in multiply with regrouping
klio [65]
First, u multiply 8x3. Only the 4 can go in the ones place so put the four beneath the line and put the 2 over the 7.
Multiply 8x7 and add 2.
Move to the tens place, do 2x3 then 2x7.
Add the products and put the comma. Then ur done

4 0
3 years ago
Reasoning Graph the set of ordered pairs (0, 2). (1.4), (2,6). (3.8). Determine whether the relationship is a linear function Ex
polet [3.4K]

Answer:

No, it does not. See below.

Step-by-step explanation:

Lets find out the linear equation that passes trough (-2, 0) and (0, -6).

We know every linear equation has the form: y = mx + b

Where m is the slope on the curve and b the independent term.

We know that, given 2 points (x1,y1) and (x2,y2) we can find the slope m as:

m = (y2-y1)/(x2-x1)

In our case lets replace (x1,y1) and (x2,y2) by (-2, 0) and (0, -6) (notice it could be done in the inverse sense where (-2, 0) is (x2,y2) and (0, -6) is (x1,y1) ). So, our slope is:

m = [-6 - 0] / [0 - (-2)]

m = -6/2 = -3

So, we have a downward linear function with slope -3, this is:

y =  -3x + b

Now, for finding b just replace any of the 2 points given in the equation. Lets replace (-2, 0):

0 = -3(-2) + b

0 = 6 + b

Subtracting 6 in both sides:

-6 = b

So, our independent term is -6 and the function is:

y = -3x - 6

Now lets see if this linear eqution passes trough (2,6). If it does, we can replace the values on the equation. Replacing x by 2:

y = -3(2) - 6 = = -6 - 6 = - 12

So, in our equation, we x is 2 y is -12, and not 6 as in the point (2,6). So, our equation does not passes trough (2,6)

5 0
2 years ago
A sweater was on sale at 40% off the regular price. Ella saved $20 by buying the sweater on sale. What was the regular price of
sladkih [1.3K]
$60, hope that helped! :)
5 0
3 years ago
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