Ask question

Ask question

All categories

3 years ago

9

traingle ABC has been dilated aboit point A by a scale factor of 1/3. What are the lengths, in units, of the three sides of tria

ngle A'B'C'

1 answer:

solniwko [45]3 years ago

4 0

Answer:

You need to show the graph so i can see numbers, you cant dilate the traingle without knowing where it is on the graph.

Step-by-step explanation:

You might be interested in

Find the value of the expression. <br> 125a^0 b^4 for a= 5/7 , b=− 1/5

bija089 [108]

Substitute the values of a nad b to the expression:

$125a^0b^4=(125)\left(\dfrac{5}{7}\right)^0\left(-\dfrac{1}{5}\right)^4=(125)(1)\left(\dfrac{1^4}{5^4}\right)\\\\=(125)\left(\dfrac{1}{625}\right)=\dfrac{125}{625}=\dfrac{125:125}{625:125}=\dfrac{1}{5}$

8 0

3 years ago

What is 10.417 rounded to the nearest hundredth?

12345 [234]

10.417 rounded to the nearest hundredth would be 10.42

8 0

3 years ago

Read 2 more answers

Factor x2 - 7x + 12.

ddd [48]

(x-4)(x-3)

FOIL to check

x² -3x -4x +12
x² -7x +12

5 0

4 years ago

Simplify each expression. Write your answers in exponential notation.

GenaCL600 [577]

$\bf ~~~~~~~~~~~~\textit{negative exponents}
\\\\
a^{-n} \implies \cfrac{1}{a^n}
\qquad \qquad
\cfrac{1}{a^n}\implies a^{-n}
\qquad \qquad
a^n\implies \cfrac{1}{a^{-n}}
\\\\[-0.35em]
\rule{34em}{0.25pt}\\\\
\left( \cfrac{36b^3}{9a^5} \right)^3\implies \left( \cfrac{4b^3}{a^5} \right)^3\implies \stackrel{\textit{distributing the exponent}}{\left(\cfrac{4^3b^{3\cdot 3}}{a^{5\cdot 3}}\right)}\implies \cfrac{64b^9}{a^{15}}$

3 0

3 years ago

The average of 5 numbers is 33. If the average of first 2 numbers is 35 and that of last 2 is 31, then find the 3rd number.

-BARSIC- [3]

The answer is c. 33.

3 0

3 years ago

Read 2 more answers