Answer:
The answer is "
f and g are arbitrary".
Step-by-step explanation:
The matrix of the device is increased
![\left[\begin{array}{ccc}1&3&f\\ c&d&g\\ \end{array}\right]](https://tex.z-dn.net/?f=%5Cleft%5B%5Cbegin%7Barray%7D%7Bccc%7D1%263%26f%5C%5C%20c%26d%26g%5C%5C%20%5Cend%7Barray%7D%5Cright%5D)
Reduce the echelon row matrix
![\left[\begin{array}{ccc}1&3&f\\ c&d&g\\ \end{array}\right] \\\\R_1 \leftrightarrow R_2 \\\\\frac{R_2 -1}{C R_1 \to R_2} \sim \left[\begin{array}{ccc} c&d&g\\ 0 & \frac{3c-d}{c}& \frac{cf-g}{c}\\ \end{array}\right]](https://tex.z-dn.net/?f=%5Cleft%5B%5Cbegin%7Barray%7D%7Bccc%7D1%263%26f%5C%5C%20c%26d%26g%5C%5C%20%5Cend%7Barray%7D%5Cright%5D%20%5C%5C%5C%5CR_1%20%5Cleftrightarrow%20%20R_2%20%5C%5C%5C%5C%5Cfrac%7BR_2%20-1%7D%7BC%20R_1%20%5Cto%20R_2%7D%20%20%20%5Csim%20%20%20%5Cleft%5B%5Cbegin%7Barray%7D%7Bccc%7D%20c%26d%26g%5C%5C%200%20%26%20%5Cfrac%7B3c-d%7D%7Bc%7D%26%20%5Cfrac%7Bcf-g%7D%7Bc%7D%5C%5C%20%5Cend%7Barray%7D%5Cright%5D)
Therefore, if 3c
0 is d
3c, the device is valid. Therefore d
are arbitrary 3c, g and f.
Answer:
B. Angle D and Angle E
C. Angle C and Angle F
Step-by-step explanation:
Alternative Interior angles are not adjacent and are at opposite sides of the transversal.
Answer:
D. There is no mistake.
Step-by-step explanation:
The following lines show the process of factorization by using common factor.
<u>Line 1:</u>
In line 1, the equation is given and is completely fine.

The only thing missing was equate to zero, but the options below talk about correct factors only, therefore this can't be considered as a mistake and can be ignored completely.
<u>Line 2:</u>
In line 2, the terms are grouped, from which we can factor out common terms.

This is also fine.
<u>Line 3:</u>
In line 3, the common term y is taken out from group 1 and 2 from other group.

which is exactly what is given in line 3.
<u>Line 4:</u>
In line 4 the common factors can be seen and easily split into 2 factors.

which is exactly what is given in line 4.
Options:
A. The grouping is correct in line 2. So this option is does not hold.
B. Common factor was factored correctly from group 1. So this option does not hold.
C. Common factor was factored correctly from group 2. So this option does not hold.
D. There is no mistake. This is correct. Thus we choose this option as correct answer.
If the power of the polynomial is 1. Then the degree of the polynomial is one.
<h3>What is the linear system?</h3>
A linear system is one in which the parameter in the equation has a degree of one. It might have one, two, or even more variables.
The linear polynomial is given below.
⇒ (7/4)x + 3
The power of the polynomial is 1.
Then the degree of the polynomial is 1.
More about the linear system link is given below.
brainly.com/question/20379472
#SPJ1
Answer:
A. point-slope form
Step-by-step explanation:
In general, the equation in point-slope form will give an expression that can substitute for "y", as that form is ...
y = [something]
_____
In specific instances, the other forms of the linear equations may work, but that is not guaranteed.