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ch4aika [34]
2 years ago
14

Write the following using algebraic notation using x as the unknown number:

Mathematics
1 answer:
andrew11 [14]2 years ago
3 0
2X-9 is this what you wanted
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Given: B = 7 −3 5 −1 C = 1 −1 13 −5 Solve the equation: 2X + B = C X =
zhuklara [117]

Answer:

-3/4 and 1/-2 is the correct answer.

Step-by-step explanation:

8 0
2 years ago
How many squares are in this figure in all?
Tanya [424]

Answer:

explanation

Step-by-step explanation:

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6 0
3 years ago
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Can someone help me find the midpoint?
ioda

Answer:

(6,-2.5)

Step-by-step explanation:

The formula for the midpoint between two points is:

(\frac{x_{1} + x_{2}}{2},\frac{y_{1}+y_{2}}{2})

Now we substitute

We have than (9, -1) is (x_{1}, y_{1}) and (3, - 4) is (x_{2}, y_{2})

So:

(\frac{(9) + (3)}{2},\frac{(-1)+(-4)}{2})\\\\(-1) + (-4) = -5\\9 + 3 = 12\\

So, we have:

(\frac{12}{2}, \frac{-5}{2})\\\\12 / 2 = 6\\-5 / 2 = -2.5\\\\(6, -2.5)

<h2>(6,-2.5)</h2><h2 />

I can do a graphic explanation if you want.

6 0
2 years ago
How many times do you need to multiply by ten to get from 19.797 to 1979.7
borishaifa [10]
You need to multiply 19.797 by 10 two times to reach 1979.7
5 0
2 years ago
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<img src="https://tex.z-dn.net/?f=%5Chuge%5Cboxed%7BQuestion%3A%7D" id="TexFormula1" title="\huge\boxed{Question:}" alt="\huge\b
iragen [17]

The equivalent expression for (x + 4)^5 is x^5+ 20x^4+ 160x^3 + 640x^2 + 1280x  + 1024

The expression is given as:

(x + 4)^5

To expand the expression, we make use of Pascal triangle, where:

5:= 1 5 10 10 5 1

So, we have:

(x + 4)^5 = 1 * x^5 * 4^0 + 5 * x^4 * 4^1  + 10 * x^3 * 4^2 + 10 * x^2 * 4^3 + 5 * x * 4^4 + 1 * x^0 * 4^5

Evaluate the exponents

(x + 4)^5 = 1 * x^5 * 1 + 5 * x^4 * 4 + 10 * x^3 * 16 + 10 * x^2 * 64 + 5 * x * 256 + 1 *1 * 1024

Evaluate the products

(x + 4)^5 = x^5+ 20x^4+ 160x^3 + 640x^2 + 1280x  + 1024

Hence, the equivalent expression for (x + 4)^5 is x^5+ 20x^4+ 160x^3 + 640x^2 + 1280x  + 1024

Read more about binomial expressions at:

brainly.com/question/13602562

7 0
2 years ago
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