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3 years ago

Can somebody please help me????

Mathematics

1 answer:

BabaBlast [244]3 years ago

6 0

PV = nRT
nR nR
PV/nR = T

  C = Wtc/1000
  1000C = Wtc
  tc tc
1000C/tc = W

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Answer:

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3 years ago

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Find the derivative with respect to x of y = (3x + x^2)^5

RSB [31]

<h2>The required "option A) $5(3x + x^2)^{4} (3+2x)$ " is correct.</h2>

Step-by-step explanation:

We have,

$y = (3x + x^2)^5$ ..... (1)

To find, $\dfrac{dy}{dx}$ = ?

Differentiating equation (1) w.r.t. 'x', we get

$\dfrac{dy}{dx}= \dfrac{d[(3x + x^2)^5]}{dx}$

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⇒ $\dfrac{dy}{dx}=5(3x + x^2)^{4} (3(1) + 2x^{2-1})$

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3 0

3 years ago

Need Help With Math. One Question

alina1380 [7]

Answer: 2 < x < 16

The triangle inequality theorem says that if we have a triangle with sides a,b,c then

b-a < c < b+a

with b being longer than 'a'

In this case, a = 7 and b = 9 and c = x

so we have

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maria [59]

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mr_godi [17]

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