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juin [17]
3 years ago
5

5 (-8n +5) -4n only right ANSWERSSS

Mathematics
2 answers:
nata0808 [166]3 years ago
7 0

−

44

n

+

25

Is the answer

−

44

n

+

25

olga55 [171]3 years ago
3 0

Answer:

-44n+25

Step-by-step explanation:

5(-8n+5)-4n

-40n+25-4n

-40n-4n+25

-44n+25

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Nico can do 42 push-ups in 3 minutes.
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Step-by-step explanation:

Hey there!

It is said we need to find the unit rate.

What we can do is apply Unitary Method.

3 minutes = 42 push ups

1 minute = \sf{\bf{\dfrac{42}{3}}}

<u>So, 12 push ups per minute is the unit rate.</u>

In 5 minutes, he will do 12×5 = <u>60 push ups!</u>

Hope it helps :)

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What is the volume of the rectangular prism?<br>183 in3<br>234 in3<br>540 in3<br>784 in3<br>​
Angelina_Jolie [31]

Answer:

C. 540 in^3

Step-by-step explanation:

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3 years ago
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An automobile manufacturer has given its car a 52.6 miles/gallon (MPG) rating. An independent testing firm has been contracted t
Arte-miy333 [17]

Answer:

Null hypothesis:\mu = 52.6  

Alternative hypothesis:\mu \neq 52.6  

z=\frac{52.8-52.6}{\frac{1.6}{\sqrt{250}}}=1.976    

p_v =2*P(z>1.976)=0.0482  

Since the p value is lower than the significance level wedon't have enough evidence to conclude that the true mean is significantly different from 52.6 MPG.

Step-by-step explanation:

Information provided

\bar X=52.8 represent the sample mean  for the MPG of the cars

\sigma=1.6 represent the population standard deviation

n=250 sample size  of cars

\mu_o =52.6 represent the value that we want to test

\alpha=0.05 represent the significance level for the hypothesis test.  

z would represent the statistic (variable of interest)  

p_v represent the p value for the test

Hypothesis

We need to conduct a hypothesis in order to check if the true mean of MPG is different from 52.6 MPG, the system of hypothesis would be:  

Null hypothesis:\mu = 52.6  

Alternative hypothesis:\mu \neq 52.6  

Since we know the population deviation the statistic is given by:

z=\frac{\bar X-\mu_o}{\frac{\sigma}{\sqrt{n}}}  (1)  

Calculate the statistic

Replacing we have this:

z=\frac{52.8-52.6}{\frac{1.6}{\sqrt{250}}}=1.976    

Decision

Since is a two tailed test the p value would be:  

p_v =2*P(z>1.976)=0.0482  

Since the p value is lower than the significance level wedon't have enough evidence to conclude that the true mean is significantly different from 52.6 MPG.

3 0
3 years ago
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