Step-by-step explanation:
At x = negative 3, limit of f (x) as x approaches negative 3 minus = negative infinity and limit of f (x) as x approaches negative 3 plus = infinity, so there is a vertical asymptote. At x = 1, limit of f (x) as x approaches 1 minus = 2 and limit of f (x) as x approaches 1 plus = 2, so there is no vertical asymptote.
At x = negative 3, limit of f (x) as x approaches negative 3 minus = infinity and limit of f (x) as x approaches negative 3 plus = negative infinity, so there is a vertical asymptote. At x = 1, limit of f (x) as x approaches 1 minus = 2 and limit of f (x) as x approaches 1 plus = 2, so there is no vertical asymptote.
At x = negative 3, limit of f (x) as x approaches negative 3 minus = negative infinity and limit of f (x) as x approaches negative 3 plus = infinity, so there is a vertical asymptote. At x = 1, limit of f (x) as x approaches 1 minus = infinity and limit of f (x) as x approaches 1 plus = infinity, so there is no vertical asymptote.
At x = negative 3, limit of f (x) as x approaches negative 3 minus = infinity and limit of f (x) as x approaches negative 3 plus = negative infinity, so there is a vertical asymptote. At x = 1, limit of f (x) as x approaches 1 minus = infinity and limit of f (x) as x approaches 1 plus = infinity, so there is no vertical asymptote.
