Answer:
The probability that exactly 19 of them are strikes is 0.1504
Step-by-step explanation:
The binomial probability parameters given are;
The probability that the pitcher throwing a strike, p = 0.675
The probability that the pitcher throwing a ball. q = 0.325
The binomial probability is given as follows;

Where:
x = Required probability
Therefore, the probability that the pitcher throws 19 strikes out of 29 pitches is found as follows;
The probability that exactly 19 of them are strikes is given as follows;
Hence the probability that exactly 19 of them are strikes = 0.1504
Answer: A
Step-by-step explanation: $88.74÷9=$9.86
$88.74 is the total amount
9 players, and each player has to pay the same amount
we have to divide it evenly in 9 pieces, so we divide $88.74 into 9 groups which then equals $9.86
Hope this helps!
Assume that 3 digits are selected at random from the set {1,3,5,6,7,8} { 1 , 3 , 5 , 6 , 7 , 8 } and are arranged in random orde
Mumz [18]
Sample space is 36.so the probability must be 20/36.from three digits the maximum no.of number can be made is 6.