Devon made a scale drawing of a triangle. He used a scale factor of One-fourth to draw the new triangle. How does each side of t
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1. You have a small typo in your answer: cubic inches is a measure of volume not surface area. Since the a TV is basically a rectangular prism, we are going to use the formula for the volume of a rectangular prism to solve this.
where
is the volume of the rectangular prism.
is the width of the base.
is the length of the base.
is the height of the prism.
We know from our problem that the television that has a total <span>volume of 75 cubic inches</span>, so
. We also know that the length of the base is 7.5 inches and the width is 4 inches, so 
and 
. Lets replace those values in our formula to find :
We can conclude that the height of the television is 2.5 inches; therefore, the correct answer is: A. 2.5 inches.
2. To solve this, we are going to use the formula for the surface area of a rectangular prism:
where
is the surface area of the rectangular prism.
is the width.
is the length.
is the height.
We know form our problem that the dimensions of our prism are:length of 12 inches, a width of 9 inches, and a height of 2 inches, so
, 
, and 
. Lets replace those values in our formula to find :
![S=2[(9in)(12in)+(2in)(12in)+(2in)(9in)]](https://tex.z-dn.net/?f=S%3D2%5B%289in%29%2812in%29%2B%282in%29%2812in%29%2B%282in%29%289in%29%5D)
We can conclude that the surface area of the prism is 300 square inches; therefore, the correct answer is: <span>D. 300</span>
where
We know from our problem that the television that has a total <span>volume of 75 cubic inches</span>, so
We can conclude that the height of the television is 2.5 inches; therefore, the correct answer is: A. 2.5 inches.
2. To solve this, we are going to use the formula for the surface area of a rectangular prism:
where
We know form our problem that the dimensions of our prism are:length of 12 inches, a width of 9 inches, and a height of 2 inches, so
We can conclude that the surface area of the prism is 300 square inches; therefore, the correct answer is: <span>D. 300</span>
Hello,
I have just answered the question
gravity on earth :g=9.81 m/s²
9.81/2≈4.9
Answer 1
2)
h(t)=-4.9*t²+20*t+10
To hit the ground ht(t)=0
==> -4.9*t²+20*t+10=0
Δ=20²+4*4*10=560=23,6643...²
t=(-20-4√35)/(-4.9*2)=4,4555...(s)
t=(-20+4√35)/(-2*4.9)=-0,37391... to exclude (time must be >0)
I have just answered the question
gravity on earth :g=9.81 m/s²
9.81/2≈4.9
Answer 1
2)
h(t)=-4.9*t²+20*t+10
To hit the ground ht(t)=0
==> -4.9*t²+20*t+10=0
Δ=20²+4*4*10=560=23,6643...²
t=(-20-4√35)/(-4.9*2)=4,4555...(s)
t=(-20+4√35)/(-2*4.9)=-0,37391... to exclude (time must be >0)