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Anuta_ua [19.1K]
2 years ago
5

F(2)=7 into coordinate points

Mathematics
1 answer:
Lisa [10]2 years ago
5 0
I don’t know how to do this type stuff so sorry hope someone els can help u tho
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WILL GIVE BRIANLEIST DONT SCASM MEQuadrilaterals LMNO and STUV are similar. What is the value of x in inches? 6.6 in. 8.2 in. 22
jeka57 [31]

Answer:

6.6 inches

Step-by-step explanation:

4.1 times 3 = 12.3

2.2 times 3 = 6.6

I think this is right... sorry if not

6 0
3 years ago
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Plot (−2 3/4, −4 1/2) on the coordinate plane.
Makovka662 [10]
Because -2 3/4 is on the x axis, it is the diagonal one, -4 1/2 is on the y axis it’s vertical.

The first number is x, the second is y.

Brainliest answer please?

7 0
3 years ago
Help please!!!I need it by tomorrow
Umnica [9.8K]

(1.) antelope sprinted the farthest

(2.) cba doing this one lol

4 0
3 years ago
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Can anybody help pls
Gekata [30.6K]

Answer:

2t

Step-by-step explanation:

The expressions are not the same because different terms are negative. We can visualize the difference by rewriting the expressions as 13t + (-2t) and (-13t) + 2t. In the first expression, 13t-2t, the 2t is negative because it is being subtracted, and subtracting a number is the same as adding a negative.

6 0
3 years ago
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i need help with this equation please there are two more possible answers that were cut off they are 17,2% and 19,5%
Margarita [4]

Consider that the experimental probability of an event is based upon the previous trials and observations of the experiment.

The experimental probability of occurrence of an event is given by,

\text{Probability of an event}=\frac{\text{ Number of outcomes that favoured the event}}{\text{ Total number of trials or outcomes}}

As per the problem, there are a total of 1230 trials of rolling a dice.

And the favourable event is getting a 2.

The corresponding experimental probability is calculated as,

\begin{gathered} P(\text{ getting a 2})=\frac{\text{ No. of times 2 occurred}}{\text{ Total no. of times the dice is thrown}} \\ P(\text{ getting a 2})=\frac{172}{1230} \\ P(\text{ getting a 2})\approx0.13984 \\ P(\text{ getting a 2})\approx13.98\text{ percent} \end{gathered}

Thus, the required probability is 13.98% approximately.

Theref

7 0
1 year ago
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