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nasty-shy [4]
3 years ago
7

Energy stored in food would be considered

Physics
1 answer:
mash [69]3 years ago
3 0

Answer:

Food contains chemical energy. Chemical energy is energy stored in bonds

Explanation:

Is this is what you meant

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A proton, starting from rest, accelerates through a potential difference of 1.0 kV and then moves into a magnetic field of 0.040
Minchanka [31]

Answer:

r = 0.11 m

Explanation:

The radius of the proton's resulting orbit can be calculated equaling the force centripetal (Fc) with the Lorentz force (F_{B}), as follows:

F_{c} = F_{B} \rightarrow \frac{m*v^{2}}{r} = qvB (1)

<u>Where:</u>

<em>m: is the proton's mass =  1.67*10⁻²⁷ kg</em>

<em>v: is the proton's velocity</em>

<em>r: is the radius of the proton's orbit</em>

<em>q: is the proton charge = 1.6*10⁻¹⁹ C</em>

<em>B: is the magnetic field = 0.040 T </em>

Solving equation (1) for r, we have:

r = \frac{mv}{qB}   (2)

By conservation of energy, we can find the velocity of the proton:

K = U \rightarrow \frac{1}{2}mv^{2} = q*\Delta V   (3)

<u>Where:</u>

<em>K: is kinetic energy</em>

<em>U: is electrostatic potential energy</em>

<em>ΔV: is the potential difference = 1.0 kV </em>

Solving equation (3) for v, we have:

v = \sqrt{\frac{2q\Dela V}{m}} = \sqrt{\frac{2*1.6 \cdot 10^{-19} C*1.0 \cdot 10^{3} V}{1.67 \cdot 10^{-27} kg}} = 4.38 \cdot 10^{5} m/s  

Now, by introducing v into equation (2), we can find the radius of the proton's resulting orbit:

r = \frac{mv}{qB} = \frac{1.67 \cdot 10^{-27} kg*4.38 \cdot 10^{5} m/s}{1.6 \cdot 10^{-19} C*0.040 T} = 0.11 m

Therefore, the radius of the proton's resulting orbit is 0.11 m.

I hope it helps you!  

5 0
3 years ago
Some earthquake waves, a cat’s purr, and elephant communications consist of ultrasonic waves.
Kobotan [32]
The answer to your question is true.
7 0
4 years ago
Read 2 more answers
If someone ways 600 newtons and the shoes have an area of 300cm squared, what pressure does he exert on the ground?
lukranit [14]
Pressure = Force / Area

Put your data in front of yourself.

Force = 600 Newtons
Area = 300 cm^2

Firstly you need to convert the area into m^2 and you do this by diving 300 with 10000.

Now you use the formula:-
Pressure = 600/ 0.03
Which comes out to be 20,000 Pa.

Hope this helps!
4 0
3 years ago
A body builder exerts 15 N of force over 3 m. How much work did she do?
tangare [24]
Work done = force x distance

work done = 15 x 3

work done = 45J
4 0
3 years ago
Read 2 more answers
An object 1 of mass m1 is separated by some distance d from an object 2 of mass 2m1 . An object 3 of mass m3 is to be placed bet
Harrizon [31]

If the potential energy of the three-object system is to be a maximum (closest to zero), should object 3 be placed closer to object 1, closer to object 2, or halfway between them?

If the potential energy of the three-object system is to be a maximum (closest to zero), should object 3 be placed closer to object 1, closer to object 2, or halfway between them?

 

Object 3 should be placed closer to object 1.

 

Object 3 should be placed on a halfway between object 2 and object 1.

 

Object 3 should be placed closer to object 2.

 

Solution

I think that Object 3 should be placed closer to object 2.

6 0
3 years ago
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