Answer:
x = 1 ±2sqrt(5)
Step-by-step explanation:
2x^2-4x-9=29
Add 9 to each each side
2x^2-4x-9+9=29+9
2x^2-4x=38
Divide by 2
2/2x^2-4/2x=38/8
x^2 -2x =19
Complete the square
x^2 -2x + (-2/2)^2 = 19 +(-2/2)^2
x^2 -2x +1 = 19+1
(x-1)^1=2 = 20
Take the square root of each side
sqrt((x-1)^2) = ±sqrt(20)
x-1 = ±sqrt(20)
Add 1 to each side
x-1+1 = 1 ±sqrt(20)
x = 1 ±sqrt(20)
Simplifying the square root of 20
x = 1 ±sqrt(4)sqrt(5)
x = 1 ±2sqrt(5)
Answer:
B. What was the highest temperature this month?
Step-by-step explanation:
Rory is recording the <em>high</em><em>est</em><em> temperature</em> for the duration of the day for month's worth of data.
B. is the easiest one to answer, as you simply will have to look for the greatest number within the set, and that will be the answer.
A. is too broad, and does not imply that only the "high temperature" is needed, rather just a leveled temperature within day in that month.
C. is the opposite of what Rory had recorded, and without data, he cannot answer it.
D. is answerable as well, but, again, the only temperature recorded is the high temperature. Temperature can fluctuate depending on the time of the day, and can be in the 50s one hour and the 90s in another.
~
Maybe B but let me check better.
Answer:
Step-by-step explanation:
finding PR ( public relations :D , not that PR , the PR on this triangle thingy )
use law of cosines, again
c=sq rt [ a^2+b^2﹣2*a*b*cos(C) ]
where
c=PR
a= 9
b = 22
C = the angle of Q or 180 = 97+24+Q so Q = 180-97-24 = 59°
they tried to trick us.. by not giving us the angle C for the above cosine formula , but we figured out their diabolical plan :D yay super hero math
then
PR = sq rt [ 9^2 + 22^2 - 2*9*22*cos(59) ]
PR = sq rt [ 81 + 484 -203.9550777 ]
( notice that now it is a subtraction sign instead of a plus sign, this time? )
PR = sq rt [361.0449 ]
PR = 19.0011
to the nearest 10th
19.0 :)
