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lisabon 2012 [21]
3 years ago
9

What is the formula for the accounting equation

Mathematics
1 answer:
ohaa [14]3 years ago
3 0

Answer:

A = L + E

Step-by-step explanation:

A = Assets

L = Liabilities

E = Equity

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The cows at the farm eat 5 3/5 hay everyday.The horses eat 1 5/6 as much as the cows. How bales of hay are the horses fed each d
Marina86 [1]

Answer:

13 2/9

Step-by-step explanation:

Cows eats=5 3/5 Hays everyday

Horses eats=1 5/6 as much as the cow

=1 5/6 of what the cow eat+5 3/5

=1 5/6 × 5 3/5 + 5 3/5

=11/6×28/6+28/6

= 308/36+28/6

=308+168/36

=476/36

=13 8/36

=13 2/9

5 0
3 years ago
Suppose the radius of a circle is \color{purple}{3}3start color purple, 3, end color purple. What is its diameter?
Varvara68 [4.7K]
The number of a radius is half of the diameter. so 3 is half of 6. your diameter is 6.
6 0
3 years ago
Evaluate when a=-6, b= 5, c= -2:<br> a3 - b + 4c2
Flura [38]

Answer:

-39

Step-by-step explanation:

a=-6 b=5 c=-2

a3-b+4c2

(-6)3-(5)+4(-2)2

8 0
3 years ago
The given matrix is the augmented matrix for a linear system. Use technology to perform the row operations needed to transform t
shtirl [24]

Answer:

x_{1} = \frac{176}{127} + \frac{71}{127}x_{4}\\\\ x_{2} = \frac{284}{127} + \frac{131}{254}x_{4}\\\\x_{3} = \frac{845}{127} + \frac{663}{254}x_{4}\\

Step-by-step explanation:

As the given Augmented matrix is

\left[\begin{array}{ccccc}9&-2&0&-4&:8\\0&7&-1&-1&:9\\8&12&-6&5&:-2\end{array}\right]

Step 1 :

r_{1}↔r_{1} - r_{2}

\left[\begin{array}{ccccc}1&-14&6&-9&:10\\0&7&-1&-1&:9\\8&12&-6&5&:-2\end{array}\right]

Step 2 :

r_{3}↔r_{3} - 8r_{1}

\left[\begin{array}{ccccc}1&-14&6&-9&:10\\0&7&-1&-1&:9\\0&124&-54&77&:-82\end{array}\right]

Step 3 :

r_{2}↔\frac{r_{2}}{7}

\left[\begin{array}{ccccc}1&-14&6&-9&:10\\0&1&-\frac{1}{7} &-\frac{1}{7} &:\frac{9}{7} \\0&124&-54&77&:-82\end{array}\right]

Step 4 :

r_{1}↔r_{1} + 14r_{2} , r_{3}↔r_{3} - 124r_{2}

\left[\begin{array}{ccccc}1&0&4&-11&:-8\\0&1&-\frac{1}{7} &-\frac{1}{7} &:\frac{9}{7} \\0&0&- \frac{254}{7} &\frac{663}{7} &:-\frac{1690}{7} \end{array}\right]

Step 5 :

r_{3}↔\frac{r_{3}. 7}{254}

\left[\begin{array}{ccccc}1&0&4&-11&:-8\\0&1&-\frac{1}{7} &-\frac{1}{7} &:\frac{9}{7} \\0&0&1&-\frac{663}{254} &:-\frac{1690}{254} \end{array}\right]

Step 6 :

r_{1}↔r_{1} - 4r_{3} , r_{2}↔r_{2} + \frac{1}{7} r_{3}

\left[\begin{array}{ccccc}1&0&0&-\frac{71}{127} &:\frac{176}{127} \\0&1&0&-\frac{131}{254} &:\frac{284}{127} \\0&0&1&-\frac{663}{254} &:\frac{845}{127} \end{array}\right]

∴ we get

x_{1} = \frac{176}{127} + \frac{71}{127}x_{4}\\\\ x_{2} = \frac{284}{127} + \frac{131}{254}x_{4}\\\\x_{3} = \frac{845}{127} + \frac{663}{254}x_{4}\\

6 0
3 years ago
Katrina saved $300 last summer. Of that amount , 12% how much Came from her allowance
masya89 [10]
The answer is 36!!!!
4 0
3 years ago
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