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PIT_PIT [208]
3 years ago
11

I need help what is 1/3x-3?​

Mathematics
1 answer:
lilavasa [31]3 years ago
8 0

Answer:

\frac{1}{3}x-3=\frac{x}{3}-3

Step-by-step explanation:

\frac{1}{3}x-3\\\\\frac{1}{3}x = \frac{x}{3}  \\\\Find\:L.C.M.\\\\=\frac{x}{3}-3

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5. The graph of a proportional relationship contains the point with coordinates (3,12).
Dmitriy789 [7]
Give me brainly and ill tell u
5 0
3 years ago
Find the length of the following curve. If you have a​ grapher, you may want to graph the curve to see what it looks like.
stepladder [879]

The length of the curve y = \frac{1}{27}(9x^2 + 6)^\frac 32 from x = 3 to x = 6 is 192 units

<h3>How to determine the length of the curve?</h3>

The curve is given as:

y = \frac{1}{27}(9x^2 + 6)^\frac 32 from x = 3 to x = 6

Start by differentiating the curve function

y' = \frac 32 * \frac{1}{27}(9x^2 + 6)^\frac 12 * 18x

Evaluate

y' = x(9x^2 + 6)^\frac 12

The length of the curve is calculated using:

L =\int\limits^a_b {\sqrt{1 + y'^2}} \, dx

This gives

L =\int\limits^6_3 {\sqrt{1 + [x(9x^2 + 6)^\frac 12]^2}\ dx

Expand

L =\int\limits^6_3 {\sqrt{1 + x^2(9x^2 + 6)}\ dx

This gives

L =\int\limits^6_3 {\sqrt{9x^4 + 6x^2 + 1}\ dx

Express as a perfect square

L =\int\limits^6_3 {\sqrt{(3x^2 + 1)^2}\ dx

Evaluate the exponent

L =\int\limits^6_3 {3x^2 + 1} \ dx

Differentiate

L = x^3 + x|\limits^6_3

Expand

L = (6³ + 6) - (3³ + 3)

Evaluate

L = 192

Hence, the length of the curve is 192 units

Read more about curve lengths at:

brainly.com/question/14015568

#SPJ1

7 0
2 years ago
0.00045−2.5⋅10 −5 = what is the answer i been up all day
Mama L [17]
If I’m getting this right the equation is: 0.00045 - 2.5 x 10 - 5? The dot in between 2.5 and 10 indicates a multiplication sign

So...

0.00045 - (2.5 x 10) - 5
0.00045 - 25 - 5
= -29.9999 -> -30
8 0
3 years ago
Please help 7n = 63 <br> n = ____
Whitepunk [10]

7 x 9 = 63

Hope this Helped:)))

6 0
3 years ago
Read 2 more answers
Find l of the following cone ​
e-lub [12.9K]

Answer:

l =  \sqrt{261}\: in

Step-by-step explanation:

Height of the cone h = 15 in

Radius of the cone r = 12/2 = 6 in

We need to find slant height (l) =?

\because l =  \sqrt{ {r}^{2}  +  {h}^{2} }  \\  \\ \therefore l =  \sqrt{ {6}^{2} +  {15}^{2}  }  \\  \\\therefore  l =  \sqrt{36 + 225}  \\  \\\therefore  l =  \sqrt{261}  \\

8 0
3 years ago
Read 2 more answers
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