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Sholpan [36]
3 years ago
15

Find the focus of the parabola whose equation is y=1/8 x^2

Mathematics
1 answer:
Mama L [17]3 years ago
7 0

Answer:

The focus is: (0,2)

Step-by-step explanation:

Given

y = \frac{1}{8}x^2

Required

Determine the focus

The focus of a parabola

(x- h)^2 = 4p(y - k)

is:

(h,k+p)

So, we have:

y = \frac{1}{8}x^2

Cross multiply

8y = x^2

Rewrite as:

x^2 = 8y

Rewrite as:

(x - 0)^2 = 8(y - 0)

Express 8 as 4 * 2

(x - 0)^2 = 4 * 2(y - 0)

By comparison with: (x- h)^2 = 4p(y - k)

h = 0    p =2     k = 0

So, the focus (h,k+p) is:

(h,k+p) = (0,0+2)

(h,k+p) = (0,2)

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