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natali 33 [55]
3 years ago
10

10 POINTS!!!

Mathematics
1 answer:
myrzilka [38]3 years ago
5 0
The correct answer for b^2 - 4ac (also known as the discriminant) should be 57 or answer C. 

You first must solve the equation for 0.
<span>1 = 2x2<span> + 7x ---> subtract 1 from each side
</span></span>0 = 2x^2 + 7x - 1

Now we can find a as the coefficient of the x^2 term, b as the coefficient for the x term an c as the number at the end. 
a = 2
b = 7 
c = -1

Now we can plug these values in for b^2 - 4ac

b^2 -4ac
(7)^2 - 4(2)(-1)
49 + 8
57
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1) AU (C - B) =
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Answer:

A \cup (C-B) = (A \cup C) \cap  (A \cup B^c)\\A \cup (B \cap C) = (A \cup B) \cap (A \cup C) \,\,\, \text{Here you use double inclusion.}\\A \cup B \cup C =  A \cup (B \cup C)\\B^c \cap (A-C)  = (B^c - C) \cap A\\(B \cap C) - A = (B-A)\cap C\\C-(A\cup B) =  (C - A )\cap B\\A^c \cap (B \cap C) = ( A^c \cap B) \cap C

Step-by-step explanation:

A \cup (C-B) = A \cup (C \cap B^c) = (A \cup C) \cap  (A \cup B^c)\\A \cup (B \cap C) = (A \cup B) \cap (A \cup C) \,\,\, \text{Here you use double inclusion.}\\A \cup B \cup C = (A \cup B ) \cup C  = A \cup (B \cup C)\\B^c \cap (A-C)  = B^c \cap (A \cap C^c) =  (B^c \cap C^c) \cap A =  (B^c - C) \cap A\\(B \cap C) - A = (B \cap C) \cap A^c  = (B \cap C) \cap A^c = (B \cap A^c)\cap C = (B-A)\cap C\\C-(A\cup B) = C \cap (A\cup B)^c = C \cap (A^c \cap B^c ) = (C  \cap A^c )\cap B^c = (C - A )\cap B\\

A^c \cap (B \cap C) = ( A^c \cap B) \cap C

3 0
3 years ago
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