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jasenka [17]
3 years ago
13

You work in the Purchasing Department for a construction company. You purchased 50 storm windows for $7,500. How much does one s

torm window cost?
Mathematics
1 answer:
Artyom0805 [142]3 years ago
3 0
Cost of 1 storm window=7500/50=$150
I hope i helped
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700

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6th grade math help me plzzz
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The answer is A, B, and D

Step-by-step explanation:

This is really easy, all you have to do is to choose the answers that are less than 1.

Why? because anything less than 1 multiplied by a number gives you a smaller number.

Since C and E are bigger than 1 then they will give you a bigger number than 2/3.

But A, B, and D are less than 1.

So, the answer is A, B, and D

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Simplify the expression. Explain each step. <br> 6(2b)
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Answer:12b

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Evaluate the Riemann sum for f(x) = 3x − 1, −6 ≤ x ≤ 4, with five subintervals, taking the sample points to be right endpoints.
Verdich [7]

Answer:

The Riemann sum equals -10.

Step-by-step explanation:

The right Riemann Sum uses the right endpoints of a sub-interval:

\int_{a}^{b}f(x)dx\approx\Delta{x}\left(f(x_1)+f(x_2)+f(x_3)+...+f(x_{n-1})+f(x_{n})\right)

where

\Delta{x}=\frac{b-a}{n}

To find the Riemann sum for \int\limits^{4}_{-6} {3x-1} \, dx with n = 5 rectangles, using right endpoints you must:

We know that a = -6, b = 4 and n = 5, so

\Delta{x}=\frac{4-\left(-6\right)}{5}=2

We need to divide the interval −6 ≤ x ≤ 4 into n = 5 sub-intervals of length \Delta{x}=2

a=\left[-6, -4\right], \left[-4, -2\right], \left[-2, 0\right], \left[0, 2\right], \left[2, 4\right]=b

Now, we just evaluate the function at the right endpoints:

f\left(x_{1}\right)=f\left(-4\right)=-13=-13

f\left(x_{2}\right)=f\left(-2\right)=-7=-7

f\left(x_{3}\right)=f\left(0\right)=-1=-1

f\left(x_{4}\right)=f\left(2\right)=5=5

f\left(x_{5}\right)=f(b)=f\left(4\right)=11=11

Finally, just sum up the above values and multiply by 2

2(-13-7-1+5+11)=-10

The Riemann sum equals -10

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Which relation is a function?
Brums [2.3K]
The second relation is a function.

For a relation to be a function, each x-value can only have a singular corresponding y-value. Since all other relations feature x-values with multiple y-values, the second relation is a function.
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