Answer:
0.08065
Step-by-step explanation:
Given that in a recent study,1 2006 randomly selected US adults (age 18 or older) were asked to give the number of people in the last six months with whom you discussed matters that are important to you.
If X is random variable then X has mean 2.2 and s = 1.4
n=2006
Std error of mean =
For 99% since sample size is large, t and z distn almost coincide.
Hence we can take 2.58 as critical value
Margin of error at 99% =
Answer:
Required Probability = 0.605
Step-by-step explanation:
Let Probability of people actually having predisposition, P(PD) = 0.03
Probability of people not having predisposition, P(PD') = 1 - 0.03 = 0.97
Let PR = event that result are positive
Probability that the test is positive when a person actually has the predisposition, P(PR/PD) = 0.99
Probability that the test is positive when a person actually does not have the predisposition, P(PR/PD') = 1 - 0.98 = 0.02
So, probability that a randomly selected person who tests positive for the predisposition by the test actually has the predisposition = P(PD/PR)
Using Bayes' Theorem to calculate above probability;
P(PD/PR) =
= =
= 0.605 .
