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andriy [413]
2 years ago
6

Which pair of functions are inverses of each other? ​

Mathematics
1 answer:
Ira Lisetskai [31]2 years ago
3 0

Answer:

D

Step-by-step explanation:

f(x) = 10x - 5 → x = 10g(x) - 5 → x + 5 = 10g(x) →

g(x) = (x + 5)/10

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aivan3 [116]

Answer:

B.)8ft

Step-by-step explanation:

Set up a proportional to the roof slope:

2/5 = x/20

Cross multiply:

40/5 = 5x/5

x=8ft

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The table shows the heights in inches of trees after they have been planted. Determine the equation which relates x and y.
fenix001 [56]
To get the that relates x and y, we choose two points on the table and use the equation of a straight line as follows:

Recall that the equation of a staight line is obtained from the formula
\frac{y-y_1}{x-x_1} = \frac{y_2-y_1}{x_2-x_1}

Using the points (30, 18) and (36, 24), we have
\frac{y-18}{x-30} = \frac{24-18}{36-30}= \frac{6}{6} =1 \\  \\ \Rightarrow y-18=x-30 \\  \\ \Rightarrow y=x-30+18 \\  \\ \Rightarrow y=x-12
8 0
3 years ago
If x^2+y^2=1, what is the largest possible value of |x|+|y|?
Marianna [84]

If <em>x</em>² + <em>y</em>² = 1, then <em>y</em> = ±√(1 - <em>x</em>²).

Let <em>f(x)</em> = |<em>x</em>| + |±√(1 - <em>x</em>²)| = |<em>x</em>| + √(1 - <em>x</em>²).

If <em>x</em> < 0, we have |<em>x</em>| = -<em>x</em> ; otherwise, if <em>x</em> ≥ 0, then |<em>x</em>| = <em>x</em>.

• Case 1: suppose <em>x</em> < 0. Then

<em>f(x)</em> = -<em>x</em> + √(1 - <em>x</em>²)

<em>f'(x)</em> = -1 - <em>x</em>/√(1 - <em>x</em>²) = 0   →   <em>x</em> = -1/√2   →   <em>y</em> = ±1/√2

• Case 2: suppose <em>x</em> ≥ 0. Then

<em>f(x)</em> = <em>x</em> + √(1 - <em>x</em>²)

<em>f'(x)</em> = 1 - <em>x</em>/√(1 - <em>x</em>²) = 0   →   <em>x</em> = 1/√2   →   <em>y</em> = ±1/√2

In either case, |<em>x</em>| = |<em>y</em>| = 1/√2, so the maximum value of their sum is 2/√2 = √2.

6 0
3 years ago
When a cylindrical tank is filled with water at a rate of 22 cubic meters per hour, the level of water in the tank rises at a ra
Sergeu [11.5K]

Answer:

r=\sqrt{10}\text{ m}

Step-by-step explanation:

We have been given that when a cylindrical tank is filled with water at a rate of 22 cubic meters per hour, the level of water in the tank rises at a rate of 0.7 meters per hour. We are asked to find the approximate radius of tank in meters.

We will use volume of cylinder formula to solve our given problem as:

V=\pi r^2h, where,

r = Radius,

h = Height of cylinder.

Since the level of water in the tank rises at a rate of 0.7 meters per hour, so height of cylinder would be h = 0.7 meters at V=22\text{ m}^3.

Upon substituting these values in above formula, we will get:

22\text{ m}^3=\frac{22}{7}\cdot r^2(0.7\text{ m})

22\text{ m}^3=\frac{22}{10}\cdot r^2\text{ m}

\frac{10}{22}\cdot\frac{22\text{ m}^3}{\text{m}}=r^2

r^2=\frac{10}{22}\cdot\frac{22\text{ m}^3}{\text{m}}

r^2=10\text{ m}^2

Now, we will take positive square root of both sides as radius cannot be negative.

\sqrt{r^2}=\sqrt{10\text{ m}^2}

r=\sqrt{10}\text{ m}

Therefore, radius of tank would be approximately square root of 10 m.

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3 years ago
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