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4 years ago

8

Smallest 3 digit number that is divisible by 3 different prime numbers

1 answer:

Sedbober [7]4 years ago

8 0

It's 102 = 2 · 3 · 17

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Which table describes the behavior of the graph of f(x) = 2x3 – 26x – 24?

In-s [12.5K]

Answer:

For x∈ {-∞,-3} y<0, below x-axis

x∈ {-3,-1} y>0, above x-axis

x∈ {-1,4} y<0, below x-axis

x∈ {4,∞} y>0, above x-axis

Step-by-step explanation:

f(x)= $2x^{3}-26x-24$

$2x^{3}-26x-24$ =0

$2x^{3}-26x-24=0\\2x^{3}-2x-24x-24=0\\2x(x^{2} -1)-24(x+1)=0\\2x(x+1)(x-1)-24(x+1)=0\\(x+1)(2x^{2} -2x-24)=0\\=> x+1=0 => x_{1}=-1\\$

$=> 2x^{2} -2x-24=0\\=>2(x^{2} -x-12)=0\\=> x^{2} -x-12=0\\=> x^{2} -4x+3x-12=0\\=> x(x-4)+3(x-4)=0\\=> (x-4)(x+3)=0\\$

$=> x-4=0\\=> x_{2}=4\\=> x+3=0\\=>x_{3}=-3\\$

For x∈ {-∞,-3} y<0, below x-axis

x∈ {-3,-1} y>0, above x-axis

x∈ {-1,4} y<0, below x-axis

x∈ {4,∞} y>0, above x-axis

7 0

4 years ago

Read 2 more answers

4,7,10,13 which has an odd product

Flauer [41]

7 & 13 have an odd product.

Hope this Helps!!

6 0

4 years ago

Read 2 more answers

<img src="https://tex.z-dn.net/?f=%20%7C%20%7Bx%7D%5E%7B2%7D%20%2B%203x%20%2B2%20%7C%20%3C%202x%20%2B%204" id="TexFormula1" titl

Snezhnost [94]

$\\ \tt\hookrightarrow |x^2+3x+2|$

Either

$\\ \tt\hookrightarrow x^2+3x+2$

$\\ \tt\hookrightarrow x^2+3x+2x$

$\\ \tt\hookrightarrow x^2+5x+6$

$\\ \tt\hookrightarrow (x+2)(x+3)$

$\\ \tt\hookrightarrow x$

Or

$\\ \tt\hookrightarrow x^2+3x+2$

$\\ \tt\hookrightarrow x^2+x-2$

$\\ \tt\hookrightarrow x^2+2x-x-2$

$\\ \tt\hookrightarrow (x+2)(x-1)$

$\\ \tt\hookrightarrow x$

So

$\\ \tt\hookrightarrow x\in (-3,1)$

7 0

2 years ago

20 Points - A mathematical model estimates sales (in thousands of dollars) as a function of time t (in years) as S(t) = 5t/t+1,

adelina 88 [10]

The first choice is the correct answer. Note that for S(t) = 5t/(t+1):At t = 0, S = 0At t = 1, S = 5(1/2)At t = 2, S = 5(2/3)And as t increases, S approaches 5. (The pattern 1/2, 2/3, 3/4...gets closer and closer to 1).

6 0

3 years ago

911!!! please answer this!!!

VikaD [51]

$\left(\dfrac{3a^{-3}b^2}{2a^{-1}b^0}\right)^2$

First some simplifying:

$\left(\dfrac{3a^1b^2}{2a^3b^0}\right)^2=\left(\dfrac{3b^2}{2a^2}\right)^2=\dfrac{9b^4}{4a^4}$

Then with $a=-2$ and $b=-3$ , we have $a^4=(-2)^4=16=4^2$ and $b^4=(-3)^4=81=9^2$ , so

$\dfrac{9b^4}{4a^4}=\dfrac{9\cdot9^2}{4\cdot4^2}=\dfrac{9^3}{4^3}=\dfrac{729}{64}$

7 0

3 years ago

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