The function that has a vertex on the y-axis is f(x) = (x - 2)(x + 2)
<h3>How to determine the function?</h3>
For a function to have its vertex on the y-axis, then the coordinate of the vertex must be:
(h,k) = (0,y)
A quadratic function is represented as:
f(x) = (x - h)^2 + k
So, we have:
f(x) = (x - 0)^2 + k
Evaluate
f(x) = x^2 + k
From the list of options, we have:
f(x) = (x - 2)(x + 2)
Expand
f(x) = x^2 - 4
Hence, the function that has a vertex on the y-axis is f(x) = (x - 2)(x + 2)
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The answer is -3
-12c = 43 - 7
-12c = 36
÷ -12 ÷-12
c = -3
It was difficult but finally i get there where 4 womens because there where 29 mens 9 swiming 6 plaiyng squash the other 14 in the gym so
18-14=4 the number of womens in the gym
Answer:
<h3>X = 142°</h3><h3>Y = 38° </h3>
<em><u>Given </u></em><em><u>-</u></em><em><u> </u></em> AC is parallel to DE
angle 3y + 28 = angle X ( Vertically opposite angles are equal).
3y + 28 = X
X + Y = 180° ( supplementary angles).
3y - X = (-28)
Solving both the equation we get
multiply eq 1 with 3
3x + 3y = 540
-X + 3y = (-28)
subtracting
4x = 568
x = 142°
3y + 28 = 142
3y = 142 - 28
3y = 114
y = 38°
Answer:
exact form: 13 over 6
decimal form: 2.16
mixed number form: 2/ 1 over 6
