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7nadin3 [17]
3 years ago
11

Find the equation of the line that goes through (1, 2) and (3, 4).

Mathematics
1 answer:
Likurg_2 [28]3 years ago
8 0

I have no idea. Just wasting your points like you do to everyone else.I have no idea. Just wasting your points like you do to everyone else.I have no idea. Just wasting your points like you do to everyone else.I have no idea. Just wasting your points like you do to everyone else.I have no idea. Just wasting your points like you do to everyone else.I have no idea. Just wasting your points like you do to everyone else.I have no idea. Just wasting your points like you do to everyone else.I have no idea. Just wasting your points like you do to everyone else.I have no idea. Just wasting your points like you do to everyone else.I have no idea. Just wasting your points like you do to everyone else.I have no idea. Just wasting your points like you do to everyone else.I have no idea. Just wasting your points like you do to everyone else.I have no idea. Just wasting your points like you do to everyone else.I have no idea. Just wasting your points like you do to everyone else.

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Evaluate C(44,21) use scientific notation, round to 3 decimal places as needed.
STALIN [3.7K]
C(44,21)=\dfrac{44!}{21!23!}=\dfrac{24\cdot25\cdot\ldots\cdot43\cdot44}{2\cdot3\cdot\ldots\cdot 20\cdot21}=2,012,616,400,080\\
\approx2.013\cdot10^{12}
6 0
3 years ago
Find the value of x. The diagram is not to scale.
tester [92]
X=15 its simple since there's base angles and straight angle
7 0
3 years ago
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What is zero to the power of 5? ill give 35 points to the first person to answer.
yan [13]

Now,

0^5

= 0

It is a right answer...

Thank you ♥♥

5 0
2 years ago
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What is the answer to this slope A (1,3),B (4,7)
jeyben [28]
The slope of these points is 4/3
7 0
3 years ago
What is the binomial expansion of (2x – 3)^5?
Tanya [424]

Answer:

C

Step-by-step explanation:

(2x + 3)^5 = C(5,0)2x^5*3^0 +

C(5,1)2x^4*3^1 + C(5,2)2x^3*3^2 + C(5,3)2x^2*3^3 + C(5,4)2x^1*3^4 + C(5,5)2x^0*3^5

Recall that

C(n,r) = n! / (n-r)! r!

C(5,0) = 1

C(5,1) = 5

C(5,2) = 10

C(5,3) = 10

C(5,4) = 5

C(5,5) = 1

= 1(2x^5)1 + 5(2x^4)3 + 10(2x^3)3^2 + 10(2x^2)3^3 + 5(2x^1)3^4 + 1(2x^0)3^5

= 2x^5 + 15(2x^4) + 90(2x^3) + 270(2x^2) + 405(2x) +243

= 32x^5 + 15(16x^4) + 90(8x^3) + 270(4x^2) + 810x + 243

= 32x^5 + 240x^4 + 720x^3 + 1080x^2 + 810x + 243

7 0
3 years ago
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