Fred works as an

Mathematics

1 answer:

OLEGan [10]3 years ago

7 0

Step-by-step explanation:

so he already down 20 ft so he ascends (goes up) 9 feet, so hes at 11 feet right now. then he descends 12 (goes down) feet so hes at 23 feet. lastly he ascends 15 feet (goes up) more. so the answer is 8

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Find lim h->0 f(9+h)-f(9)/h if f(x)=x^4 a. 23 b. -2916 c. 2916 d. 2925

Svetach [21]

$\displaystyle\lim_{h\to0}\frac{f(9+h)-f(9)}h = \lim_{h\to0}\frac{(9+h)^4-9^4}h$

Carry out the binomial expansion in the numerator:

$(9+h)^4 = 9^4+4\times9^3h+6\times9^2h^2+4\times9h^3+h^4$

Then the 9⁴ terms cancel each other, so in the limit we have

$\displaystyle \lim_{h\to0}\frac{4\times9^3h+6\times9^2h^2+4\times9h^3+h^4}h$

Since h is approaching 0, that means h ≠ 0, so we can cancel the common factor of h in both numerator and denominator:

$\displaystyle \lim_{h\to0}(4\times9^3+6\times9^2h+4\times9h^2+h^3)$

Then when h converges to 0, each remaining term containing h goes to 0, leaving you with

$\displaystyle\lim_{h\to0}\frac{f(9+h)-f(9)}h = 4\times9^3 = \boxed{2916}$

or choice C.

Alternatively, you can recognize the given limit as the derivative of f(x) at x = 9:

$f'(x) = \displaystyle\lim_{h\to0}\frac{f(x+h)-f(x)}h \implies f'(9) = \lim_{h\to0}\frac{f(9+h)-f(9)}h$

We have f(x) = x ⁴, so f '(x) = 4x ³, and evaluating this at x = 9 gives the same result, 2916.

8 0

3 years ago

What is the radical number for 62

a_sh-v [17]

Answer:

The square root of 62 in its simplest form means to get the number 62 inside the radical √ as low as possible. The square root of 62 is already in the simplest radical form. Therefore, the answer is √62.

Step-by-step explanation:

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3 years ago

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Joey pays $35.85 each month for his new stereo what does he pay each year

maks197457 [2]

ANSWER
$430.20

STEP BY STEP
there are 12 months in a year so multiply that number by 12.

Hope this helps

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2 years ago

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Please let me know

bazaltina [42]