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kvasek [131]
2 years ago
8

A mass of 100 g stretches a spring 5 cm. If the mass is set in motion from its equilibrium position with a downward velocity of

50 cm/s, and if there is no damping, determine the position u of the mass at any time t. (Use g = 9.8 m/s2 for the acceleration due to gravity. Let u(t), measured positive downward, denote the displacement in meters of the mass from its equilibrium position at time t seconds). What does u(t) equal?When does the mass first return to its equilibrium position? (What does t in seconds equal?)
Mathematics
1 answer:
Over [174]2 years ago
4 0

Answer:

Step-by-step explanation:

Given that:

mass m = 100 g = 0.1 kg

Length of the spring = 5 cm = 0.05 m

The set in motion from the equilibrium position u(0) = 0

The set in motion from its equilibrium position with a downward velocity u'(0) = 50 cm/s = 0.5 m/s

The spring constant (k) = \dfrac{0.1 \times 9.8}{0.05}

The equation of the system is expressed as:

\dfrac{1}{10} u'' + \dfrac{98}{5} u =0

By estimating the characteristics equation, we have r = ± 14i

Thus; the general solution is:

u(t) = c_1cos  \ 14t + c_2 sin 14 \ t

By applying the initial condition:

u(0) = 0

⇒ 0 = c_1

∴

\dfrac{du}{dt} = ( - c_1 \ sin 14 t )\times 14 +14c_2 \ cos 14 t

u'(0) = 0.5

0.5 = 14 × c₂

c₂ = 0.5/14

c₂ = 1/28

∴

\mathbf{u(t) = \dfrac{1}{28} sin 14 t}

Equating u(t) = 0, we have t = π/14sec as the time when the mass first returns to its equilibrium position.

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topjm [15]

Answer:

D

Step-by-step explanation:

Exponential equation takes the form  y=a*b^x  where

  1. a is the initial value ( a ≠ 0), and
  2. b is the base ( b ≠ 1)

The equation given in the problem can be written as  y=-4.8*4^x, so it is <em>an exponential equation, </em>  where a = -4.8 and b = 4.

Thus we can say that the initial value = -4.8 and the base is 4

The correct answer is  D

3 0
3 years ago
It is generally claimed that the average body temperature for healthy human adults is 98.6°F. To test this claim a simple random
Rzqust [24]

Answer:

Explained below.

Step-by-step explanation:

The information provided is as follows:

\mu=98.6^{o}F\\\bar x=98.1^{o}F\\s=0.9^{o}F\\n=9

(1)

A single mean test is to be performed in this case.

As the population standard deviation is not provided, a one-sample <em>t</em>-test will be used.

The correct option is b.

(2)

The null hypothesis is:

<em>H</em>₀: The average temperature in the population is 98.6°F, i.e. <em>μ </em>= 98.6°F.

The correct option is b.

(3)

The alternative hypothesis is:

<em>Hₐ</em>: The average temperature in the population is less than 98.6°F, i.e. <em>μ </em>< 98.6°F.

The correct option is c.

(4)

The standard deviation of the sample mean is as follows:

SD_{\bar x}=\frac{s}{\sqrt{n}}=\frac{0.9}{\sqrt{9}}=0.3^{o}F

Thus, the value of SD is 0.3°F.

(5)

Compute the value of test statistic as follows:

t=\frac{\bar x-\mu}{SD_{\bar x}}

  =\frac{98.1-98.6}{0.3}\\\\=-1.666666667\\\\\approx -1.67

Thus, the value of test statistic is -1.67.

(6)

The degrees of freedom of the test are:

df = n - 1

   = 9 - 1

   = 8

Thus, the degrees of freedom of the test is 8.

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3 years ago
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Answer:

her total profit is 3

Step-by-step explanation:

1.50 x 30 = 45

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3 years ago
The population of two different villages is modeled by the equations shown
vlada-n [284]

Answer:

Year = 1995 and population = 315

Year = 2015 and population = 715

Step-by-step explanation:

It is given that the population of two different villages is modeled by the given equations:

y=x^2-30x+540

y=20x+15

The population of both villages are same after x years after 1980 if

x^2-30x+540=20x+15

x^2-30x+540-20x-15=0

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Splitting the middle term, we get

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(x-15)(x-35)=0

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It means, after 15 or 35 years, the population will same.

For x=15, years is 1980+15=1995 and population is  

y=20(15)+15=315

For x=35, years is 1980+35=2015 and population is  

y=20(35)+15=715.

Therefore, population are equation in Year = 1995 and population = 315 or Year = 2015 and population = 715.

7 0
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