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spayn [35]
3 years ago
8

Please help ill give brainliest for sure to the right answer

Mathematics
2 answers:
storchak [24]3 years ago
8 0

Answer:

linear and increasing

Blababa [14]3 years ago
6 0

Answer:

linear and increasing

Step-by-step explanation:

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ivanzaharov [21]
Equation C. :) lalalalalala
3 0
3 years ago
Find the volume of a cone with a base radius of 3 cm and a height of 9 cm
katovenus [111]

The volume of a cone is 84.78 cm                

<u>Step-by-step explanation</u>:

<u>Given</u>:

radius = 3 cm and

height = 9 cm

<u>To Find</u>:

The Volume of a Cone

<u>Formula</u>:

The Formula for the volume of a cone is

V=πr2 *h/3

<u>Solution</u>:

V=πr2 *h/3

π value is 3.14

V= 3.14*(3)^2*9/3

V=3.14*9*3

V= 84.78 cm

Therefore the volume is 84.78 cm.

5 0
4 years ago
9. In a rhombus whose side measures 34 and the smaller angle is 42°. Find the length of the larger diagonal, to the nearest tent
Veseljchak [2.6K]

Answer:

63.5

Step-by-step explanation:

The diagonals of a rhombus bisect opposite angles.

The longer diagonal bisects the 42° angle

The larger angle of the rhombus is 180 - 42 = 138

Let x = the length of the longer diagonal

You know two sides and the included angle of a triangle.

Using the law of cosines we get

x^{2} = 34^{2} + 34^{2} -2(34)(34) cos 138\\         = 1156 + 1156 - 2312 cos 138\\         = 4030.150837...\\x = \sqrt{4030.150837} = 63.48x^{2} = 34^{2} + 34^{2} -2(34)(34)cos 138\\         = 1156 + 1156 - 2312 cos 138\\         = 4030.1508...\\     x = \sqrt{4030.1508} \\          =  63.48x^2 = 34^2 + 34^2 - 2(34)(34) cos 138

      = 1156 + 1156 - 2312 c0s 138

      = 4030.1508...

x = sq rt 4030.1508...

  =  63.5

7 0
3 years ago
What is the solution to the equation
Tresset [83]

Solution:

Given Expression is 1/40* x = 1/8

Step : Define x in the Equation:

Step : Divide the Equation by 8

Step : Do cross multiplication

Step : Arrange it in particular form

____________________________

☞ 1/40x = 1/8

☞ x/40 = 1/8

☞ x = ⅛ × 40

☞ x = 5

.

Therefore, Answer is 5.

5 0
3 years ago
Read 2 more answers
the length of a rectangle is 5 inches longer than twice the width and the area is 12 inches squared. Let l represent the length
svet-max [94.6K]

Answer:

Length = 8 inch , Width = \frac{3}{2} , This equation models the situation

Step-by-step explanation:

Given as ;

The Area of Rectangle is 12 inches²

The Length of Rectangle is 5 inches longer than twice the width

Let The Length = L inches

      The Width   = W inches

According to question ,

L = 5 + (2 × w )

∵ The Area of Rectangle = Length × width

Or, 12  inches²  = [ 5 + (2 × w ) ] ×  w

Or,  12  inches² = 5 w +2 w²

Or,  2 w² + 5 w  - 12 = 0

Or,   2 w² + 8 w  -3 w - 12 = 0

Or,  2 w (w +4) - 3 (w + 4) = 0

I.e (w + 4) ( 2 w - 3) = 0

So ,  w = -4 , and w = \frac{3}{2}

∴  Length = 5 + (2 × w ) =

   Length = 5 + (2 ×\frac{3}{2}  )  

so ,  L = 5 + 3 = 8

Hence Length = 8 inch , Width = \frac{3}{2}   This equation models the situation Answer

3 0
3 years ago
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