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Bumek [7]
3 years ago
11

27.893m in _______m_____dm______cm_____mm​

Mathematics
1 answer:
aliina [53]3 years ago
6 0

Answer:

27.893m in <u>27</u>m <u>8</u>dm 9cm <u>3</u>mm​

Step-by-step explanation:

Just put in the digits from left to right since:

10dm = 1m

10cm = 1 dm

10mm = 1cm

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A geometric sequence has first term 1/9 and common ratio 3. Which is the first term of the sequence which exceeds 1000?
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Simplifying this, we get:
\frac{1}{9} (3)^{-1} (3)^n

Since we're finding the first term that exceeds 1000, let's set it equal to 1000.

\frac{1}{27}(3)^n=1000
Multiplying both sides by 27
3^n=27000

log_{3}27000=n

n≈9.2

We have to round n up, since if n=9, the value would be <1000.
Therefore n=10. Substituting n=10,
\frac{1}{27}3^{10}
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Therefore the first term that exceeds 1000 is 2187, and it is the 10th term
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3 years ago
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prisoha [69]
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6 0
3 years ago
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Shtirlitz [24]
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