Let X be a random sample representing the score of a student in the American Chemical Society Examination.
P(450 < x < 500) = P((450 - 500)/(90/sqrt(25)) < z < (500 - 500)/(90/sqrt(25))) = P(-2.778 < z < 0) = P(z < 0) - P(z < -2.778) = P(z < 0) - [1 - P(z < 2.778)] = P(z < 0) + P(z < 2.778) - 1 = 0.5 + 0.99727 - 1 = 0.49727 = 49.7%
2x-7 * x
----------- =. 100^2= 10000
2
2x^2-7/2= x^2-7/2
x^2-7/2=10000
x^2 = 20007/7
Remember:
a^m * a^n=a^(m+n)
a^-m=1/a^m
8³ x 8⁻⁵=8³⁻⁵=8⁻²=1/8²=1/64<1
Answer: the student is not correct, because 1/64<1, and 8³ x 8⁻⁵=1/64.
Answer:
243 in²
Step-by-step explanation:
Step 1. Calculate the<em> base and height </em>of the rectangle
We have two conditions:
(1) 2b+ 2h = 72 in
(2) b = 3h Substitute in (1)
2(3h) + 2h = 72 Remove parentheses
6h + 2h = 72 Combine like terms
8h = 72 Divide by 6
h = 9 in Substitute in(2)
b = 3 × 9
b = 27 in
Step 2. Calculate the area of the rectangle
A = bh
A = 27 × 9
A = 243 in²
The area of the rectangle is 243 in².
