Answer:
Kate policy will pay 1500 dollars while Johns policy will pay 250 dollars
Explanation:
kates policy will pay 1500 dollars while johns policy will pay 250 dollars.
Since Kates deductible is 500 dollars, this deductible will be subtracted from the 2000 dollars collission loss that occurred when John borrowed her car. which gives $1500. therefore her policy will get to pay 1500 dollars. while johns policy will have to pay $250
John's reaction is an example of the bystander effect.
It means that he will just continue staring at the accident because he is curious as to what happened and he wants to see how the event is resolved, however, he is not really willing to do anything to help the people involved - he will just assume someone else will do that.
Review sessions are important as they are there to clear out the doubts over a semester.
Explanation:
IT is important to determine what to study before review sessions so as to remove blind spots from the assessment of the whole course which would then lead to a lack of coverage in the overall coverage of the curriculum which can be disastrous later on.
The student must know what they want out of the review session for it to be successful and fruitful for them in the first place and this importance cannot be overstated by the fact that it is the last chance to remove the said blind spots from the curriculum.
Answer:
$24135.72
Explanation:
Given pmt 320, r 9% n 5 years
This amount is paid monthly s\and there are 12 months in a year
r = 9%/12 =0.75%
n = 5* 12 =60
We will use the future value of annuity
FV = pmt *[(1+r)^n - 1/r)]
= 320 *[(1+0.0075)^60-1/0.0075
=$24135.72
Answer:
Standard deviation = 47.69% (Approx)
Explanation:
Given:
Portfolio of Apple stock w1 = 25% = 0.25
Portfolio of Tesla stock w2 = 75% = 0.75
Standard deviation return Apple σ1 = 35% = 0.35
Standard deviation return Tesla σ2 = 60% = 0.60
Correlation coefficient ρ12 = 0.22
Find:
Standard deviation
Computation:
Standard deviation = √w1²σ1² + w2²σ2² + 2w1σ1w2σ2ρ12
Standard deviation = 0.4769
Standard deviation = 47.69% (Approx)
