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Harman [31]
3 years ago
12

NEED HELP REALLY FAST!!!!!!!!!

Mathematics
2 answers:
Andrei [34K]3 years ago
8 0
The answer is 10, hopefully this helps:)
omeli [17]3 years ago
6 0
I think the answer would be 8 :) hope this helps !
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PLEASE HELP!!!
zloy xaker [14]

Answer:

D

Step-by-step explanation:

8 0
3 years ago
Explain how to solve 4|3x-1|+1=8​
denis-greek [22]

4|3x - 1| + 1 = 8

4|3x - 1| = 8 - 1

4|3x - 1| = 7

|3x - 1| = 7/4

Now lets think, we have 3x - 1 in module, so either its 7/4 or -7/4, we will have 7/4 at the end because of it, so we may have 2 solutions in this case:

3x - 1 = 7/4

and

3x - 1 = -7/4

So let's see:

3x - 1 = 7/4

3x = 7/4 + 1

3x = 11/4

x = 11/12

3x - 1 = -7/4

3x = -7/4 + 1

3x = -3/4

x = -1/4

So we have two possible answers, x = 11/2 and x = -1/4

8 0
3 years ago
Tim has to cover 3 tanks completley with paint. ​
bija089 [108]

<em>answer:</em>

<h3><em>Total </em><em>surface </em><em>area </em><em>of </em><em>3</em><em> </em><em>tanks=</em><em>3</em><em>4</em><em>.</em><em>3</em><em> </em><em>m^</em><em>2</em></h3><h3><em>7</em><em> </em><em>tins </em><em>of </em><em>paint </em><em>are </em><em>required</em><em>.</em></h3>

<em>Solution</em><em>,</em>

<em>diameter </em><em>of </em><em>tank=</em><em>1</em><em>.</em><em>4</em><em> </em><em>m</em>

<em>Height </em><em>of </em><em>tank=</em><em>1</em><em>.</em><em>9</em><em> </em><em>m</em>

<em>Given </em><em>tank </em><em>has </em><em>top </em><em>and </em><em>bottom </em>

<em>Now,</em><em> </em><em>The </em><em>total </em><em>surface </em><em>area </em><em>of </em><em>cylinder </em><em>tank </em><em>is </em><em>given </em><em>by:</em>

<em>tsa = 2\pi \:  {r}^{2}  + (2\pi \: r \: ) \times h</em>

<em>r(</em><em> </em><em>radius </em><em>of </em><em>tank)</em><em>=</em>

<em>\frac{diameter}{2}  =  \frac{1.4}{2}  = 0.7 \: m</em>

<em>h(</em><em>height </em><em>of </em><em>tank)</em><em>=</em><em>1</em><em>.</em><em>9</em><em> </em><em>m</em>

<em>TSA </em><em>of </em><em>1</em><em> </em><em>tank</em>

<em>=</em>

<em>2 \times 3.14 \times  {(0.7)}^{2}  + 2 \times 3.14 \times 0.7 \times 1.9 \\  = 11.435 \:  {m}^{2}</em>

<em>TSA </em><em>Of </em><em>3</em><em> </em><em>tanks</em>

<em>=</em>

<em>3 \times 11.435 \:  {m}^{2}  \\  = 34.3 \:  {m}^{2}</em>

<em>Given </em><em>a </em><em>tin </em><em>of </em><em>plate </em><em>covers </em><em>5</em><em>m</em><em>^</em><em>2</em><em> </em><em>area.</em>

<em>No.of </em><em>tins </em><em>required:</em>

<em>1</em><em> </em><em>tin</em><em> </em><em> </em><em> </em><em> </em><em> </em><em> </em><em> </em><em>5</em><em>m</em><em>^</em><em>2</em>

<em>x </em><em>tin</em><em> </em><em> </em><em> </em><em> </em><em> </em><em> </em><em> </em><em> </em><em>3</em><em>4</em><em>.</em><em>3</em><em> </em><em>m^</em><em>2</em>

<em>5x = 34.3(cross \: multiplication) \\ or \: x =  \frac{34.3}{5}  \\ x = 6.86 \\ x = 7 \: tins</em>

<em>there</em><em>fore</em><em> </em><em>7</em><em> </em><em>tins </em><em>are </em><em>required</em><em>.</em>

<em>Hope </em><em>this </em><em>helps.</em><em>.</em><em>.</em>

<em>Good </em><em>luck</em><em> on</em><em> your</em><em> assignment</em><em>.</em><em>.</em><em>.</em><em>.</em>

8 0
3 years ago
$400 at 6.5% for 3 years
RSB [31]

At the end of 3 years, your savings will have grown to $483.

You will have earned in $83.17 in interest.

4 0
3 years ago
Which undefined terms are needed to define perpendicular lines?
SVETLANKA909090 [29]
C is the answer lil flock
7 0
4 years ago
Read 2 more answers
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